Question

n a clinical trial, 18 out of 860 patients taking a prescription drug daily complained of flulike symptoms. Suppose that it is known that 1.7% of patients taking competing drugs complain of flulike symptoms. Is there sufficient evidence to conclude that more than 1.7% of this drug's users experience flulike symptoms as a side effect at the alpha equals 0.05 level of significance? Because np 0 left parenthesis 1 minus p 0 right parenthesisequals 14.4 greater than 10, the sample size is less than 5% of the population size, and the sample can be reasonably assumed to be random, the requirements for testing the hypothesis are satisfied. (Round to one decimal place as needed.) What are the null and alternative hypotheses? Upper H 0: p equals 0.017 versus Upper H 1: p greater than 0.017 (Type integers or decimals. Do not round.) Find the test statistic, z 0. z 0equals 0.89 (Round to two decimal places as needed.) Find the P-value. P-valueequals 0.186 (Round to three decimal places as needed.) Choose the correct conclusion below. A. Since P-valueless thanalpha, reject the null hypothesis and conclude that there is sufficient evidence that more than 1.7% of the users experience flulike symptoms. B. Since P-valuegreater thanalpha, reject the null hypothesis and conclude that there is not sufficient evidence that more than 1.7% of the users experience flulike symptoms. C. Since P-valuegreater thanalpha, do not reject the null hypothesis and conclude that there is not sufficient evidence that more than 1.7% of the users experience flulike symptoms. Your answer is correct.D. Since P-valueless thanalpha, do not reject the null hypothesis and conclude that there is sufficient evidence that more than 1.7% of the users experience flulike symptoms. please show all work

Answer #1

Ans:

Because np 0(1- p 0)= 14.4 greater than 10, the sample size is less than 5% of the population size, and the sample can be reasonably assumed to be random, the requirements for testing the hypothesis are satisfied.

H_{0}:p=0.017

H_{1}:p>0.017

sample proportion=18/860=0.02093

Test statistic:

z=(0.02093-0.017)/SQRT(0.017*(1-0.017)/860)

z=**0.89**

p-value=P(z>0.89)**=0.186**

correct option is:

Since P-value is **greater than** alpha,
**do not reject the null hypothesis** and conclude
that there is **not sufficient evidence** that more
than 1.7% of the users experience flu like symptoms.

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