Question

In a clinical trial, 26 out of 866 patients taking a prescription drug daily complained of flulike symptoms. Suppose that it is known that 2.7% of patients taking competing drugs complain of flulike symptoms. Is there sufficient evidence to conclude that more than 2.7% of this drug's users experience flulike symptoms as a side effect at the alpha equals 0.1 level of significance?

Because np0 (1 – p0) = ____ ____ 10, the sample size is ________ 5% of the population size, and the sample _________________ the requirements for testing the hypothesis ______ satisfied.

What are the null and alternative hypotheses?

H0: _______ versus H1: ___________

Find the test statistic, z0.

Z0 = _____ (round to two decimal places as needed)

Find the P-value.

P-value = _____ (round to three decimal places as needed)

Choose the correct conclusion below.

Since P-valuegreater thanalpha, reject the null hypothesis and conclude that there is not sufficient evidence that more than 2.4% of the users experience flulike symptoms.

Since P-valuegreater thanalpha, do not reject the null hypothesis and conclude that there is not sufficient evidence that more than 2.4% of the users experience flulike symptoms.

Since P-valueless thanalpha, reject the null hypothesis and conclude that there is sufficient evidence that more than 2.4% of the users experience flulike symptoms.

Since P-valueless thanalpha, do not reject the null hypothesis and conclude that there is sufficient evidence that more than 2.4% of the users experience flulike symptoms.

Answer #1

p0 = 0.027, n = 866

np0 (1 – p0) = 866 * 0.027 * (1 - 0.027) = 22.75069

Because np0 (1 – p0) = ____ >____ 10, the sample size is ___is less than_____ 5% of the population size, and the sample ____can be reasonable assumed to be random_____________ the requirements for testing the hypothesis are satisfied.

What are the null and alternative hypotheses?

H0: **p0 = 0.027** versus H1: **p0 >
0.027**

Standard error of proportion, SE = = 0.005507815

Sample proportion, p = 26 / 866 = 0.03

Z0 = (p - p0)/SE = (0.03 - 0.027)/ 0.005507815
= **0.54**

Find the P-value.

P-value = P(z > 0.54) = **0.295**

alpha = 0.1

Choose the correct conclusion below.

**Since P-value greater than alpha, do not reject the
null hypothesis and conclude that there is not sufficient evidence
that more than 2.4% of the users experience flulike
symptoms.**

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>
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