Question

4. Use the formula for the acceleration found at point 3 to calculate the “calculated acceleration”...

4. Use the formula for the acceleration found at point 3 to calculate the “calculated acceleration” in Data Table for any given hanging mass m.

5. Determine the percentage difference between the values of acceleration calculated using the equation at point 3) and the values measured using the experiment.
%error = | ameasuredacalculated| ×100 / acalculated
and write them in the table.

PART III: CONCLUSIONS

1. Give a reasonable explanation for your percent difference. What can be the source of discrepancies? “Human error” is not an explanation.

2. What relationships exist between these variables (as indicated by your data)? a. Force and acceleration ________________

b. total mass and acceleration: ________________

3. Check your understanding
Q1. Newton’s second law indicates that when a net force acts on an object, it must accelerate. Does it mean that when two or more forces are applied to an object simultaneously, it must accelerate? Explain.

Q2. The net external force acting on an object is zero. Is it possible for the object to be traveling with a velocity that is not zero? If your answer is yes, state whether any conditions must be placed on the magnitude and direction of the velocity. If your answer is no, provide a reason for your answer.

Q3. All of the following, except one, cause the acceleration of an object to be reduced by a factor of two. Which one is it? Explain.
a) The net force acting on an object is reduced by a factor of two.
b) The net force acting on the object is doubled.

c) All forces acting on the object are reduced by a factor of two. d) The mass of the object is doubled.

Homework Answers

Answer #1

1.)

friction and air resistance can alter the results and give a data different from theoretical

2.)

a) F = ma

b) m = F/a

3)

q1)

NO.
Two or more forces can cancel out each other. Hence, it is not necessary that it will always cause acceleration.

q2)

Yes.

If the body is already moving at some speed and 0 netforce is applied. It will continue to move at same speed as before. No constraint of magnitude or direction.

q3)

b) If net force is doubled, acceleration double too.

As per F = ma

accn is directly proportional to force

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