What is the average kinetic energy of a proton at 15 million K? What is the closest distance two protons with this energy can approach each other? How many proton radii is this? The radius of the proton is 10^-15 m.
Average energy of a proton will be given by:
E = kT
at T = 15 x 106 K,
E = 1.38 x 10-23 x 15 x 106 = 2.07 x 10-16 J = 1293.75 eV
Let d be the distance between the protons. So, if the electromagnetic energy of two proton system were to be equal to their thermal energy of 1293.75 eV, then the electromagnetic energy can be given by:
=> d = 1.11 x 10-12 m = 1113 times the radius of a proton.
this is the closest distance two protons with this energy can approach each other.
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