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A length of wire has a resistance of 1620 Ω. The wire is cut into N...

A length of wire has a resistance of 1620 Ω. The wire is cut into N identical pieces which are then connected in parallel. The resistance of the parallel arrangement is 20.0 Ω. Find N.

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Answer #1

Given Resistance R =1620 ohms

Resistance of parallel arrangement R| =20 ohms.

If the wire is cut into N identical pieces and are connected in parallel then the

equation is given by


substitute values

Therefore, the wire is cut into N= 9 identical pieces.

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