An electron and a proton each have a thermal kinetic energy of 3kBT/2. Calculate the de Broglie wavelength of each particle at a temperature of 2090 K. (kb is Boltzmann's constant, 1.38x10-23 J/K).
1)Wavelength of the electron = m
2) Wavelength of the proton = m
Thermal kinetic energy of electron or proton
Mass of electron
Mass of proton
We know
de Broglie wavelength
Now
Planck's constant
1)
2)
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