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Alpha particles of a certain initial kinetic energy are projected at nuclei with atomic number Z...

Alpha particles of a certain initial kinetic energy are projected at nuclei with atomic number Z = 45. The closest distance of approach of the alpha particles to the nucleus is 100 fm (fm = femtometer = 10-15 m). If alpha particles of the same initial kinetic energy are projected at nuclei with atomic number 82, what is the distance of closest approach? Give your answer in fm. (Enter the number only -- do not include the units in your answer.)

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Comment the distance of closest approach was found to be 182.22 fm

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