Light in the air is incident at an angle to a surface of (12.0 + A) degrees on a piece of glass with an index of refraction of (1.10 + (B/100)). What is the angle between the surface and the light ray once in the glass? Give your answer in degrees and rounded to three significant figures.
A= 6
B= 41
Angle to the surface of air - glass = 12 + A = 12 + 6 = 18 degrees (Given A=6)
Angle of incidence i = 90 - 18 = 72 degrees
Refractive index of glass = μ = 1.10 + (B/100)=1.1 + (41/100) = 1.51 (Given B=41)
μ = sin i / sin r r = angle of refraction = ?
sinr = sini / μ = sin72 / 1.51 = 0. 298
r = sin-1 (0.6298) = 39 degrees
Angle between surface and light ray once in the glass = 90 - 39 = 51 degrees
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