Question

Consider two materials with indices of refraction, n1 = (1.20 + (A/100)) and n2 = (1.10 + (B/100)). Determine the critical angle for light traveling from material 1 to material 2. Give your answer with three significant figures.

A= 7

B= 1

Light in the air is incident at an angle to a surface of (12.0 + A) degrees on a piece of glass with an index of refraction of (1.10 + (B/100)). What is the angle between the surface and the light ray once in the glass? Give your answer in degrees and rounded to three significant figures.

A= 6

B= 41

Answer 1

1)

n1=1.2+(A/100)=1.2+(7/100)=1.27 (A=7)

n2 = 1.10 + (B/100)=1.1+(1/100)=1.11   (B=1)

n2/n1=sinC                             C=critiacal angle=?

1.11/1.27=sinC

sinC=0.874

C=sin-1(0.874)=60.9 degree2)

Angle to the surface of air - glass=12+A=12+6=18 degree           (A=6)

Angle of incidence i=90-18=72 degree

refractive index of glass   n= 1.10 + (B/100)=1.1+(41/100)=1.51     (B=41)

n=sini/sinr                   r=angle of refraction=?

sinr=sini/n=sin72/1.51=.6298

r=sin-1(.6298)=39 degree

Angle between surface and light ray in glass=90-39=51degree