A light beam strikes a piece of glass at a 68.00 ∘incident angle. The beam contains two wavelengths, 450.0 nm and 700.0 nm, for which the index of refraction of the glass is 1.4831 and 1.4754, respectively. 
Part A What is the angle between the two refracted beams? Express your answer using two significant figures.

angle of incidence theta1 = 68 deg
refractive index of the glass is
n2 = 1.4831 (for 450 nm)
n2' = 1.4754 (for 700 nm)
by using snell's law,
n1*sin(theta1) = n2*sin(theta2)
for 450 nm,
n1*sin(theta1) = n2*sin(theta2)
1*sin(68) = 1.4831*sin(theta2)
sin(theta2) = sin(68)/1.4831
theta2 = 38.694 deg
and
for 700 nm,
n1*sin(theta1) = n2'*sin(theta2')
1*sin(68) = 1.4754*sin(theta2')
sin(theta2') = sin(68)/1.4754
theta2' = 38.934 degrees
angle between the refracted beam is
= (theta2')  (theta2)
= 0.234 deg.
Get Answers For Free
Most questions answered within 1 hours.