Question

The ammonia molecule NH₃ has a permanent electric dipole moment equal to 1.47D, where 1D = debye unit = 3.34

Answer 1

The electric potential due to an ammonia molecule at a point r = 52 nm away along

the axis of the dipole is

V = k * (p/r²)

where k = (1/4??o) = 9 * 10⁹ Nm2/C2,

p = 1.47D = 1.47 * 3.34 * 10^-30 C* m = 4.9 * 10^-30 C* m

and r = 60 nm = 60 * 10^-9 m

V =9x10⁹*4.9x10^-30/(60x10^-9) ² = 0.01225x10^-3 V

V = 1.23 x10^-5 Volts
-----------------------------------------------
b)

The electric field along the axis of the dipole is

Edipole = k * (p/r³)= V/r = 1.23x10^-5/(60x10^-9) = 205 V/m
--------------------------------------------------

ALL THE BEST