Question

In the figure, a 6.67 g bullet is fired into a 0.376 kg block
attached to the end of a 0.320 m nonuniform rod of mass 0.407 kg.
The block-rod-bullet system then rotates in the plane of the
figure, about a fixed axis at *A*. The rotational inertia of
the rod alone about *A* is 0.0986 kg·m^{2}. Treat
the block as a particle. **(a)** What then is the
rotational inertia of the block-rod-bullet system about point
*A*? **(b)** If the angular speed of the system
about *A* just after impact is 3.15 rad/s, what is the
bullet's speed just before impact?

Answer #1

A uniform thin rod of length 0.56 m and mass 3.2 kg can rotate
in a horizontal plane about a vertical axis through its center. The
rod is at rest when a 3.5 g bullet traveling in the rotation plane
is fired into one end of the rod. As viewed from above, the
bullet's path makes angle θ = 60° with the rod. If the
bullet lodges in the rod and the angular velocity of the rod is
12.0 rad/s...

A bullet of mass m = 8.00 g is fired into a block of
mass M = 180 g that is initially at rest at the edge of a
table of height h = 1.00 m (see figure below). The bullet
remains in the block, and after the impact the block lands
d = 2.10 m from the bottom of the table.
Determine the initial speed of the bullet.
m/s

A 10 g bullet is fired into a 9.0 kg wood block that is at rest
on a wood table. The block, with the bullet embedded, slides 5.0 cm
across the table. The coefficient of kinetic friction for wood
sliding on wood is 0.20. What was the speed of the bullet?

13. A 10.0-g bullet is fired into a stationary block of wood
(m = 5.00 kg) at the speed of 300 m/s, the
relative motion of the bullet stops inside the block. Determine the
speed of the bullet-plus-wood combination immediately after the
collision.

A bullet with mass m1 = 3.00 g is fired into a wooden block of
mass m2 = 1.00 kg, that hangs like a pendulum. The bullet is
embedded in the block (complete inelastic collision). The block
(with the bullet embedded in it) goes h = 30.0 cm high after
collision. Calculate the speed of the bullet before it hit the
block.

A 10 g bullet with speed vbullet0 is fired into a 1.000 kg wood
block (vblock0 = 0), where it lodges. Subsequently, the block
slides 4.0 m across a wood floor (μk = 0.20 for wood on wood). What
was the bullet’s speed vbullet0?

A 7.00 g bullet, when fired from a gun into a 0.90 kg block of
wood held in a vise, penetrates the block to a depth of 9.20 cm.
This block of wood is next placed on a frictionless horizontal
surface, and a second 7.00 g bullet is fired from the gun into the
block.
To what depth will the bullet penetrate the block in this case?
cm

A 1.42 kg block is attached to a horizontal spring with spring
constant 3100 N/m . The block is at rest on a frictionless surface.
A 8.40 g bullet is fired into the block, in the face opposite the
spring, and sticks.
Part A
What was the bullet's speed if the subsequent oscillations have
an amplitude of 14.3 cm ?

A 50 gram lead bullet is fired at 450 m/s to a 3 kg block of
copper and penetrates the block. Assuming that the bullet does not
leave the block, if the initial temperature of the bullet is 60°C
and the block is originally at 30°C,
a) Find the final temperature of the bullet-block system.
(Assume that the system is isolated and there is no heat escaping
the system)
b) Is the dissipated energy (due to the collision) enough to...

A bullet with mass m(lowercase m) is fired into a block of wood
with mass M(uppercase M), suspended like a pendulum, and makes a
completely inelastic collision with it. After the impact of the
bullet, the block swings up to a maximum height h. Given the values
of h = 5.00 cm = 0.0500 m, m = 6.75 g = 0.00675 kg, and M = 2.50
kg, (a) What is the (initial) velocity v_x of the bullet in m/s?
(b)...

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