Question

a particle is moving along a ball y = t ^ 2 so at any time...

a particle is moving along a ball y = t ^ 2 so at any time vx= 3 feet / s. Calculate the magnitude the direction of the velocity and the acceleration of the particle at the point x = 2/3
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Answer #1

motion in y direction is given by

velocity in y direction is

acceleration in y direction is given by

in x direction velocity is constant

therefore acceleration in x direction will be zero

time when the position of the particle is x=2/3

therefore at t=2/9 seconds

magnitude of velocity

direction

counterclockwise from the positive x direction

calculation of magnitude of acceleration

therefore magnitude of acceleration is 1ft/sec2

direction is along positive y axis as the acceleration in x direction is zero

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