Question

a particle is moving along a ball y = t ^ 2 so at any time...

a particle is moving along a ball y = t ^ 2 so at any time vx= 3 feet / s. Calculate the magnitude the direction of the velocity and the acceleration of the particle at the point x = 2/3
Science   Advanced-Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

motion in y direction is given by

velocity in y direction is

acceleration in y direction is given by

in x direction velocity is constant

therefore acceleration in x direction will be zero

time when the position of the particle is x=2/3

therefore at t=2/9 seconds

magnitude of velocity

direction

counterclockwise from the positive x direction

calculation of magnitude of acceleration

therefore magnitude of acceleration is 1ft/sec2

direction is along positive y axis as the acceleration in x direction is zero

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The position ? of a particle moving in space from (t=0 to 3.00 s) is given...
The position ? of a particle moving in space from (t=0 to 3.00 s) is given by ? = (6.00?^2− 2.00t^3 )i+ (3.00? − ?^2 )j+ (7.00?)? in meters and t in seconds. Calculate (for t = 1.57 s): a. The magnitude and direction of the velocity (relative to +x). b. The magnitude and direction of the acceleration (relative to +y). c. The angle between the velocity and the acceleration vector. d. The average velocity from (t=0 to 3.00 s)....
.The x and y components of the velocity of a particle are: vx = (2 t...
.The x and y components of the velocity of a particle are: vx = (2 t + 4) p / s vy = (8 ⁄ y) p / s Initially, the particle is located at the coordinates x = 1 and y = 0. Determine the position, the magnitude of the velocity and the magnitude of the particle's acceleration when t = 2 s.
A particle travels along the path defined by the parabola y=0.2x^2. If the component of velocity...
A particle travels along the path defined by the parabola y=0.2x^2. If the component of velocity along t he x axis is Vx=(2.9t)ft/s, where t is in seconds. determine the magnitude of the particle's acceleration when t = 1s. when t = 0 , x =0 and y = 0.
The velocity of a particle moving along the x-axis varies with time according to v(t) =...
The velocity of a particle moving along the x-axis varies with time according to v(t) = A + Bt−1, where A = 7 m/s, B = 0.33 m, and 1.0 s ≤ t ≤ 8.0 s. Determine the acceleration (in m/s2) and position (in m) of the particle at t = 2.6 s and t = 5.6 s. Assume that x(t = 1 s) = 0. t = 2.6 s acceleration  m/s2 position  m ? t = 5.6 s acceleration  m/s2   position  m ?
The velocity-time graph of a particle moving along the x-axis is shown. The particle has zero...
The velocity-time graph of a particle moving along the x-axis is shown. The particle has zero velocity at t = 0.00 s and reaches a maximum velocity, vmax, after a total elapsed time, ttotal. If the initial position of the particle is x0 = 7.29 m, the maximum velocity of the particle is vmax = 11.3 m/s, and the total elapsed time is ttotal = 25.0 s, what is the particle's position at t = 16.7 s? b. At t...
The function s(t) describes the position of a particle moving along a coordinate line, where s...
The function s(t) describes the position of a particle moving along a coordinate line, where s is in feet and t is in seconds. s(t) = 3t2 - 6t +3 A) Find the anti-derivative of the velocity function and acceleration function in order to determine the position function. To find the constant after integration use the fact that s(0)=1. B) Find when the particle is speeding up and slowing down. C) Find the total distance from time 0 to time...
The x and y components of the velocity of a particle are Vx=(2t + 4)ft/s &...
The x and y components of the velocity of a particle are Vx=(2t + 4)ft/s & Vy=(8/y)ft/s. Initially, the particle if found at coordinates x=1 and y=0. Determine the position, magnitude of velocity, and magnitude of the acceleration of the particle when t = 2s
1-The velocity of a particle is v = { 6 i + ( 28 - 2...
1-The velocity of a particle is v = { 6 i + ( 28 - 2 t ) j } m/s, where t is in seconds. If r=0 when t=0, determine particle displacement during time interval t = 3 s to t = 8 s in the y direction. 2-A particle, originally at rest and located at point (1 ft, 4 ft, 5 ft), is subjected to an acceleration of a={ 3 t i + 17 t2k} ft/s. Determine magnitude...
A particle is moving along a straight line and has acceleration given by a(t) = 20t^3+12t^2}....
A particle is moving along a straight line and has acceleration given by a(t) = 20t^3+12t^2}. Its initial velocity is v( 0 ) = 4 m / s and its initial displacement is s( 0 ) = 5 m. Find the position of the particle at t = 1 seconds.
The position of a particle moving along the x axis is given in centimeters by x...
The position of a particle moving along the x axis is given in centimeters by x = 9.75 + 2.50t 3, where t is in seconds. Consider the time interval t = 2.00 s to t = 3.00 s. (a) Calculate the average velocity. (b) Calculate the instantaneous velocity at t = 2.00 s. (c) Calculate the instantaneous velocity at t = 3.00 s. (d) Calculate the instantaneous velocity at t = 2.50 s. (e) Calculate the instantaneous velocity when...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT