Question

The velocity-time graph of a particle moving along the x-axis is
shown. The particle has zero velocity at t = 0.00 s and reaches a
maximum velocity, *v*_{max}, after a total
elapsed time, *t*_{total}. If the initial
position of the particle is *x*_{0} = 7.29 m, the
maximum velocity of the particle is
*v*_{max} = 11.3 m/s, and the total elapsed
time is *t*_{total} = 25.0 s, what is the
particle's position at t = 16.7 s?

b. At t = 16.7 s, what is the particle's velocity?

c. At t = 16.7 s, what is the particle's acceleration?

Answer #1

The velocity of a particle moving along the x-axis
varies with time according to
v(t) = A +
Bt−1,
where
A = 7 m/s,
B = 0.33 m,
and
1.0 s ≤ t ≤ 8.0 s.
Determine the acceleration (in m/s2) and position (in
m) of the particle at
t = 2.6 s
and
t = 5.6 s.
Assume that
x(t = 1 s) = 0.
t = 2.6 s
acceleration m/s2 position m
?
t = 5.6 s
acceleration m/s2
position m ?

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