Question

Make sure you note left or right and which lens you are referring. An object is placed in front of two thin lenses with focal lengths f1=-20 cm & f2=9.0 cm, with a lens separation of L=10.0 cm. The object is 9.0 cm from lens 1. Where is the image of the object? What is the magnification of the image? 12.

Answer #1

An object is placed 246 cm to the left of a positive lens of
focal length +17.9 cm. A second positive lens, of focal length
+35.3 cm is placed to the right of the first lens with a separation
of 101 cm. Calculate the position of the final image relative to
the second lens. (Report a positive number if the image is to the
right of the second lens, and a negative number if it is to the
left of...

An object is placed 187 cm to the left of a positive lens of
focal length +100 cm. A second positive lens, of focal length +150
cm is placed to the right of the first lens with a separation of
83.4 cm. Calculate the position of the final image relative to the
second lens. (Report a positive number if the image is to the right
of the second lens, and a negative number if it is to the left of...

A 2.05-cm-tall object is placed 30.0 cm to the left of a
converging lens with a focal length f1 = 20.5 cm . A diverging
lens, with a focal length f2 = -42.5 cm , is placed 30.0 cm to the
right of the first lens.
Q:How tall is the final image of the object?

A 2.05-cm-tall object is placed 30.0 cm to the left of
a converging lens with a focal length f1 = 21.0 cm . A diverging
lens, with a focal length f2 = -42.5 cm , is placed 30.0 cm to the
right of the first lens.
How tall is the final image of the object?________cm

A 2.05-cm-tall object is placed 30.0 cm to the left of a
converging lens with a focal length f1 = 20.0 cm . A diverging
lens, with a focal length f2 = -50.0 cm , is placed 30.0 cm to the
right of the first lens. You may want to review (Pages 959 - 966) .
How tall is the final image of the object?

Part 1
Two thin converging lenses of focal lengths f1 = 9.6 cm and f2 =
12 cm are separated by a = 20 cm, as in the figure below. An object
is placed p1 = 15 cm to the left of the first lens. Find the
position of the final image from the second lens. Answer in units
of cm.
Part 2
What is the magnification of the second lens?
Part 3
Calculate the magnification of the whole system.

A simple camera telephoto lens consists of two lenses. The
objective lens has a focal length f1 = 38.8 cm . Precisely
36.0 cm behind this lens is a concave lens with a focal length
f2 = -10.0 cm . The object to be photographed is 4.02 m in
front of the objective lens.
How far behind the concave lens should the film be placed
What is the linear magnification of this lens combination?

A simple camera telephoto lens consists of two lenses. The
objective lens has a focal length f1 = 39.5 cm . Precisely 36.5 cm
behind this lens is a concave lens with a focal length f2 = -10.0
cm . The object to be photographed is 3.96 m in front of the
objective lens How far behind the concave lens should the film be
placed? What is the linear magnification of this lens
combination?

A converging lens of focal length f1 = +22.5 cm is placed at a
distance d = 60.0 cm to the left of a diverging lens of focal
length f2 = −30.0 cm. An object is placed on the common optical
axis of the two lenses with its base 45.0 cm to the left of the
converging lens. (The thin-lens approximation may be assumed to
hold.) (a) Calculate the location of the final image and its
overall magnification with respect...

Two converging lenses are placed 15 cm
apart. The lens A (on the left) has a focal length of 5 cm, and
lens B (on the right) has a focal length of 4 cm. An object is
placed 8 cm to the left of lens A. Draw the scenario and confirm
your findings using the equations to find:
a) the final
image distance
b) the
magnification
c) is the
image real or virtual?

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