Question

When a mass is far away from the moon it has a speed 3.2 times
its escape velocity from the moon. With what speed in metres per
second must the object have be launched from the surface of the
moon? (M_{moon} = 7.36 X 10^{22} kg;
R_{moon} = 1.74 X 10^{6} kg)

The answer is 7970 m/s. Consider initial and final energy conditions

Answer #1

Problem: Trip to the moon
You plan to take a trip to the moon. Since you do not have a
traditional spaceship with rockets, you will need to leave the
earth with enough speed to make it to the moon. Some information
that will help during this problem:
mearth = 5.9742 x 1024 kg
rearth = 6.3781 x 106 m
mmoon = 7.36 x 1022 kg
rmoon = 1.7374 x 106 m
dearth to moon = 3.844 x 108 m...

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P1:Suppose an object is launched from Earth with 0.52 times the
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an object on Earth's surface. For this problem, neglect Earth's
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For reference, Earth's mass is 5.972 x 1024 kg.
Your...

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What is the gravitational potential energy of the moon with
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What is the binding energy of the moon to Earth?
What is the total mechanical energy of the moon in its
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The escape velocity from a massive object is the speed needed to
reach an infinite distance from it and have just slowed to a stop,
that is, to have just enough kinetic energy to climb out of the
gravitational potential well and have none left. You can find the
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surface of the Moon at a temperature of the Moon's...

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(b) If the probe is to achieve a maximum distance
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Zero, a hypothetical planet, has a mass of 5.8 x 1023
kg, a radius of 3.4 x 106 m, and no atmosphere. A 10 kg
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(a) If the probe is launched with an initial
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(b) If the probe is to achieve a maximum distance
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