Question

1- Write a function float computeArea (int *v1, int *v2, int shape ) that computes the area of four basic geometric entities. The geometric entity will be identified by the argument shape which is 1 for triangle, 2 for square/rectangle and 3 for circle. The arguments v1 and v2 are pointers to the two arguments defining the shape. For circle v1 is a pointer to the diameter of the circle, v2 is null, for rectangle/square, v1 and v2 are pointers to the height and width for triangle v1 is a pointer to the the base and v2 points to the height of the triangle.

2- Write a function that accepts a string and a character as input and returns the number of times the character given as the second argument appears in the string. int numTimesAppears(char *mystring, char ch) “Yusuf Ozturk” and letter u is passed as arguments the function should return 3.

Answer 1

#include <stdio.h>

float computeArea(int *v1, int *v2, int shape) {
    if (shape == 1) {
        return 0.5 * (*v1) * (*v2);
    } else if (shape == 2) {
        return (*v1) * (*v2);
    } else {
        return (3.14 * (*v1) * (*v1)) / 4;
    }
}

int numTimesAppears(char *mystring, char ch) {
    int count = 0, i = 0;
    while (mystring[i]) {
        if (mystring[i] == ch) {
            ++count;
        }
        i++;
    }
    return count;
}

int main(void) {
    char mystring[] = "Yusuf Ozturk";
    char ch;
    float area;
    int length, height, diameter, base;
    int count;

    length = 10;
    height = 5;
    base = 20;
    diameter = 6;

    area = computeArea(&base, &height, 1);
    printf("\nThe area of the triangle is %f", area);

    area = computeArea(&length, &height, 2);
    printf("\nThe area of the square or rectangle is %f", area);

    area = computeArea(&diameter, &diameter, 3);
    printf("\nThe area of a circle is %f", area);

    ch = 'u';
    count = numTimesAppears(mystring, ch);
    printf("\nNumber of times %c appears in string is %d", ch, count);
    return 0;
}