Question

An unstable particle at rest breaks up into two fragments of unequal mass. The mass of the lighter fragment is equal to 2.50 10-28 kg and that of the heavier fragment is 1.67 10-27 kg. If the lighter fragment has a speed of 0.893c after the breakup, what is the speed of the heavier fragment? c

Answer #1

In such case of collison, linear momentum is conserved.

An unstable particle at rest breaks up into two fragments of
unequal mass. The mass of the lighter fragment is equal to
3.80 ✕ 10−28 kg and that of the heavier fragment is 1.75
✕ 10−27 kg. If the lighter fragment has a speed of
0.893c after the breakup, what is the speed of the heavier
fragment? c=

An unstable particle is at rest and suddenly breaks up into two
fragments. No external forces act on the particle or its fragments.
One of the fragments has a velocity of +0.772c and a mass of 2.81 ×
10-27 kg, and the other has a mass of 4.32 × 10-27 kg. What is the
velocity of the more massive fragment (as a multiple of c)?

An unstable particle is at rest and suddenly decays into two
fragments. No external forces act on the particle or its fragments.
One of the fragments has a speed of 0.76c and a mass of
6.68×10?27kg, while the other has a mass of 1.67×10?27kg.
What is the speed of the less massive fragment?

An unstable particle is at rest and suddenly decays into two
fragments. No external forces act on the particle or its fragments.
One of the fragments has a speed of 0.56c and a mass of
6.68×10−27kg, while the other has a mass of 1.67×10−27kg.
What is the speed of the less massive fragment?

An unstable particle with a mass equal to 3.34 ✕ 10−27 kg is
initially at rest. The particle decays into two fragments that fly
off with velocities of 0.971c and −0.851c, respectively. Find the
masses of the fragments. (Hint: Conserve both mass–energy and
momentum.) m(0.971c) = kg m(-0.851c) = kg

An unstable mass particle with a mass equal to3.34 X
10-27 kg is initially at rest. The particle decays into
two fragments that fly off with velocities of 0.971c and -0.851c,
respectively. Find the masses of the fragments (Hint: conserve both
mass-energy and momentum.)

An unstable particle with a mass equal to 3.34 ✕
10−27 kg is initially at rest. The particle decays into
two fragments that fly off with velocities of 0.979c and
−0.851c, respectively. Find the masses of the fragments.
(Hint: Conserve both mass–energy and momentum.)
m(0.979c) =
m(-0.851c) =

A bomb at rest explodes into three fragments. Two of these
fragments with mass m1 = 2 kg, and m2 = 1 kg respectively, travel
in left direction; the other fragment with mass m3 = 3 kg travels
in opposite direction. If the velocities of fragments 1 and 2 are
v1 = 5 m/s and v2 = 2 m/s respectively, find the velocity of
fragment 3.

An unstable nucleus of mass 1.7 ✕ 10−26 kg, initially at rest
at the origin of a coordinate system, disintegrates into three
particles. One particle, having a mass of
m1 = 2.6 ✕ 10−27 kg,
moves in the positive y-direction with speed
v1 = 5.4 ✕ 106 m/s.
Another particle, of mass
m2 = 8.0 ✕ 10−27 kg,
moves in the positive x-direction with speed
v2 = 3.4 ✕ 106 m/s.
Find the magnitude and direction of the velocity of...

A 1300 kg weather rocket accelerates upward at
10m/s2. It explodes 1.8 s after liftoff and breaks into
two fragments, one twice as massive as the other. Photos reveal
that the lighter fragment traveled straight up and reached a
maximum height of 580 m .
What was the speed of the heavier fragment just after the
explosion?

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