Question

A bomb at rest explodes into three fragments. Two of these fragments with mass m1 = 2 kg, and m2 = 1 kg respectively, travel in left direction; the other fragment with mass m3 = 3 kg travels in opposite direction. If the velocities of fragments 1 and 2 are v1 = 5 m/s and v2 = 2 m/s respectively, find the velocity of fragment 3.

Answer #1

According to conservation of linear momentum,

The momentum of an isolated system remains constant. Momentum is said to be conserved over time; that is, momentum is neither created nor destroyed, only transformed from one form to another.

Momentum before explosion = Momentum after collision

Let M be the total mass of bomb and u initial velocity.

According to sign convention,velocity towards right is taken positive and towards left, negative

Initially at rest, implies

Velocity of fragment 3 is **4 m/s** towards
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