Question

on the earth, a 3 kg steel ball on a string oscillates 45 times in 145 seconds. how long is the string? if the experiment is performed on the moon what is the new period of the pendulum?

Answer #1

The given period of the oscillation of the string ball is

*T* = 145 seconds / 45

= 3.22 seconds

The period of oscillation is

Here, length of the string is *L* and acceleration due to
gravity is *g*.

Subsitute the values,

Therefore, the length of the string is **2.57**
**m**.

Again, the acceleration due to gravity on the Moon is

*g*_{M} = *g*/6

= 9.8 m/s^{2} / 6

= 1.63 m/s^{2}

Thus, the period of pendulum when the experiment is conducted on the Moon is

Rounding off to three significant figures, the period of the
pendulum when the experiment is conducted on the Moon is
**9.91 s**.

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