Question

A pendulum consists of a 5.2 kg ball suspended by a 1.3 m length of string with negligible mass and is initially at rest. A 4.4 g bullet travelling at 680 m/s is fired horizontally into the ball and is lodged there. The ball and bullet rise together to a maximum height of h. How long does it take from the moment of impact for the ball to first reach its maximum height?

Answer #1

**momentum before bullet struck the ball Pi =
m*vo**

**momentum after bullet struck the ball Pf = ( M
+m)v**

**total momentum is conserved**

**momentum before collision = moemntum after
collision**

**Pi = Pf**

**m*vo = (M+m)*v**

**4.4*10^-3*680 = ( 5.2 + (4.4*10^-3) )*V**

**speed of bullet + ball = 0.575 m/s
<<<---answer**

**after the bullet is struck**

**total energy of the bullet + ball Ei =
(1/2)*(M+m)*v^2**

**the bullet + block system reaches a height
h**

**at the height h energy**

**Ef = (M + m)*g*h**

**total energy is conserved**

**Ef = Ei**

**(M+m)*g*h = (1/2)*(M+m)*v^2**

**h = v^2/(2g)**

**h = 0.575^2/(2*9.81)**

**h = 0.017 m <<<------answer**

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