Question

Solve the initial value problem (xy' = 2y + x^ 3 + 1, y(1) = 1/2, x > 0

Answer #1

Solve the initial value problem xy′ +2y = e^x2 , y(1) = −2

Solve the Initial Value Problem:
?x′ = 2y−x
y′ = 5x−y
Initial Conditions:
x(0)=2
y(0)=1

In Exercises 31-42, solve the initial value problem.
3(x^(2))y''-4xy'+2y=0, y(1)=2, y'(1)=1

For the initial value problem
• Solve the initial value problem.
y' = 1/2−t+2y withy(0)=1

Solve the initial value problem.
x'=x+2y
y'=7x+y
with inition contitions x(0)=2 and y(0)=4.

Solve the initial value problem.
d^2y/dx^2= -3 csc^2 x; y' (pi/4)=0; y(pi/2)=0
The solution is y=____.

Solve the initial value problem below.
x2y''−xy'+y=0, y(1)=1, y'(1)=3
y=

For 2y' = -tan(t)(y^2-1) find general solution (solve for y(t))
and solve initial value problem y(0) = -1/3

for the given initial value problem: (2-t)y' + 2y
=(2-t)3(ln(t)) ; y(1) = -2
solve the initial value problem

Solve the following initial value problem.
y''-2y'+2y=4x+5. ; y(0)=3. and y'(0)=0

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