Question

Solve the initial value problem. d^2y/dx^2= -3 csc^2 x; y' (pi/4)=0; y(pi/2)=0 The solution is y=____.

Solve the initial value problem.

d^2y/dx^2= -3 csc^2 x; y' (pi/4)=0; y(pi/2)=0

The solution is y=____.

Math   Calculus   
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