Question

Solve the initial value problem xy′ +2y = e^x2 , y(1) = −2

Answer #1

Solve the initial value problem.
(?2+1)?′+2?=1+?where?(0)=2(x2+1)y′+2y=1+xwherey(0)=2

For the initial value problem
• Solve the initial value problem.
y' = 1/2−t+2y withy(0)=1

Use Laplace transform to solve the following initial value
problem: y '' − 2y '+ 2y = e −t , y(0) = 0 and y ' (0) =
1
differential eq

for the given initial value problem: (2-t)y' + 2y
=(2-t)3(ln(t)) ; y(1) = -2
solve the initial value problem

Solve the given initial-value problem. y''' − 2y'' + y' = 2 −
24ex + 40e5x, y(0) = 1/2 , y'(0) = 5/2 , y''(0) = − 5/2

For 2y' = -tan(t)(y^2-1) find general solution (solve for y(t))
and solve initial value problem y(0) = -1/3

Solve the Initial Value Problem:
?x′ = 2y−x
y′ = 5x−y
Initial Conditions:
x(0)=2
y(0)=1

In Exercises 31-42, solve the initial value problem.
3(x^(2))y''-4xy'+2y=0, y(1)=2, y'(1)=1

Solve the initial value problem. 5d^2y/dt^2 + 5dy/dt -
y = 0; y(0)=0, y'(0)=1

solve diffeential equation.
( x2y +xy -y )dx + (x2 y -2 x2)
dy =0 answer x + ln x + x-1 + y- 2 lny = c
dy / dx + 2y = e-2x - x^2 y (0) =3 answer
y = 3 e -2s + e-2x ( intefral of e
-s^2ds ) s is power ^ 2 means s to power of
2

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