Question

For 2y' = -tan(t)(y^2-1) find general solution (solve for y(t)) and solve initial value problem y(0) = -1/3

Answer #1

Solve the Initial Value Problem:
dydx+2y=9,
y(0)=0
dydx+ycosx=5cosx,
y(0)=7d
Find the general solution, y(t)y(t), which solves the problem
below, by the method of integrating factors.
8tdydt+y=t3,t>08tdydt+y=t3,t>0
Put the problem in standard form.
Then find the integrating factor,
μ(t)=μ(t)= ,__________
and finally find y(t)=y(t)= __________ . (use C as the
unkown constant.)
Solve the following initial value problem:
tdydt+6y=7ttdydt+6y=7t
with y(1)=2.y(1)=2.
Put the problem in standard form.
Then find the integrating factor, ρ(t)=ρ(t)= _______ ,
and finally find y(t)=y(t)= _________ .

Find y(t) solution of the initial value problem
3ty^2y'-6y^3-4t^2=0, y(1)=1, t>0

For the initial value problem
• Solve the initial value problem.
y' = 1/2−t+2y withy(0)=1

Solve the Initial Value Problem:
a) dydx+2y=9, y(0)=0 y(x)=_______________
b) dydx+ycosx=5cosx,
y(0)=7d y(x)=______________
c) Find the general solution, y(t), which solves the problem
below, by the method of integrating factors.
8t dy/dt +y=t^3, t>0
Put the problem in standard form.
Then find the integrating factor, μ(t)= ,__________
and finally find y(t)= __________ . (use C as the unkown
constant.)
d) Solve the following initial value problem:
t dy/dt+6y=7t
with y(1)=2
Put the problem in standard form.
Then find the integrating...

solve the initial value problem y''-2y'+5y=u(t-2) y(0)=0
y'(0)=0

for the given initial value problem: (2-t)y' + 2y
=(2-t)3(ln(t)) ; y(1) = -2
solve the initial value problem

solve the given initial value problem
dx/dt=7x+y x(0)=1
dt/dt=-6x+2y y(0)=0
the solution is x(t)= and y(t)=

find y(t) solution of the initial value problem
y'=(2y^2 +bt^2)/(ty), y(1)=1 t>o

Solve the initial value problem y''−y'−2y=0, y(0) = α, y'(0) =2.
Then ﬁnd α so that the solution approaches zero as t →∞

Solve the initial value problem below for the Cauchy-Euler
equation
t^2y"(t)+10ty'(t)+20y(t)=0, y(1)=0, y'(1)=2
y(t)=

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