Question

for the given initial value problem: (2-t)y' + 2y
=(2-t)^{3}(ln(t)) ; y(1) = -2

solve the initial value problem

Answer #1

For the initial value problem
• Solve the initial value problem.
y' = 1/2−t+2y withy(0)=1

For 2y' = -tan(t)(y^2-1) find general solution (solve for y(t))
and solve initial value problem y(0) = -1/3

Solve the given initial-value problem. y''' − 2y'' + y' = 2 −
24ex + 40e5x, y(0) = 1/2 , y'(0) = 5/2 , y''(0) = − 5/2

Use Laplace transforms to solve the given initial value
problem.
y"-2y'+5y=1+t y(0)=0 y’(0)=4

Solve the initial value problem below for the Cauchy-Euler
equation
t^2y"(t)+10ty'(t)+20y(t)=0, y(1)=0, y'(1)=2
y(t)=

Please solve the listed initial value problem:
y'' + 3y' + 2y = 1 - u(t - 10); y(0) = 0, y'(0) = 0

solve the initial value problem y''-2y'+5y=u(t-2) y(0)=0
y'(0)=0

Solve the given initial-value problem. (x + 2) dy dx + y =
ln(x), y(1) = 10 y(x) =
Give the largest interval I over which the solution is defined.
(Enter your answer using interval notation.)
I =

solve the given initial value problem
dx/dt=7x+y x(0)=1
dt/dt=-6x+2y y(0)=0
the solution is x(t)= and y(t)=

In Exercises 31-42, solve the initial value problem.
3(x^(2))y''-4xy'+2y=0, y(1)=2, y'(1)=1

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