Ans. Profit function, P = -0.003n^2 + 5.4n - 1211
a) To break even means earning zero profits,
=> P = 0
=> -0.003n^2 + 5.4n - 1211 = 0
=> n = 263.56 or 1537.44units
Thus, 1537 soccer balls (this is because increasing output from 263 to 1537 does not reduced the profit) should be made in order to break even.
b) To maximize the profit, differentiate the profit fuction with respect to n and then equate it to zero,
=> dP/dn = -0.006n + 5.4 = 0
=> n = 900 units
So, 900 soccer balls should be made to maximize profits.
c) Maximum profit, P = -0.003*900^2 + 5.4*900 -1211
=> Maximum Profit = $1219
d) To earn a profit of $677,
677 = -0.003*n^2 +5.4n - 1211
=> n = 474.95 or 1325.05 units
So, to earn a profit of $677, the production will be 1325 units (because after 1325.05 profits start decreasing)
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