Question

If X1 has 1000, X9 has 77, and memory locations 1000, 1008, and 1016 have 100, 200, 300 respectively, what do X2 have after the following instructions?
LDUR X2, [X1, #16]
ADD X2, X1, X2

Answer 1

LDUR - Load unscaled Register.It loads the value from the address plus the offset given.here the base register won't be modified

LDUR R₁,[R₂,Imm] --- loads the  value at the memory address (R₂ + imm) [Imm - immediate] to R1 and the base register R₂ is not modified

For the given question

LDUR X2,[X1,#6] --- the value present at (1000+16) is loaded into X2

so now X2 = 300 (because the value present at the address 1016 is 300)

ADD X2,X1,X2

X2 = X1+X2

X2 = 1000+300

X2 = 1300