Self-isolation for Coronavirus
In the context of the current pandemic situation, the Ottawa Health Agency (OHA) was interested to know how Ottawa residents support their recommended self-isolation instructions related to the novel Coronavirus. They commissioned a professional agency to do a survey of 1000 individuals living in the city in March 2020 and obtained the following results:
Support of OHA Self-Isolation Instructions
Support |
Oppose |
Total |
|
Returning travellers |
69 |
81 |
150 |
Non-travellers who had contact |
243 |
207 |
450 |
Non-travellers who didn’t have contact |
300 |
100 |
400 |
What is the population of interest?
Question 13 options:
Ottawa residents who participated in the survey |
|
Ottawa residents in March 2020 |
|
Ottawa citizens |
Question 14 (1 point)
Self-isolation for Coronavirus
In the context of the current pandemic situation, the Ottawa Health Agency (OHA) was interested to know how Ottawa residents support their recommended self-isolation instructions related to the novel Coronavirus. They commissioned a professional agency to do a survey of 1000 individuals living in the city in March 2020 and obtained the following results:
Support of OHA Self-Isolation Instructions
Support |
Oppose |
Total |
|
Returning travellers |
69 |
81 |
150 |
Non-travellers who had contact |
243 |
207 |
450 |
Non-travellers who didn’t have contact |
300 |
100 |
400 |
Which of the following best describes the purpose of this exercise?
Question 14 options:
Descriptive statistics about a sample |
|
Inferring information about a population from information about a sample |
|
Descriptive statistics about a population |
|
Inferring information about a sample from information about a population |
Question 15 (1 point)
Self-isolation for Coronavirus
In the context of the current pandemic situation, the Ottawa Health Agency (OHA) was interested to know how Ottawa residents support their recommended self-isolation instructions related to the novel Coronavirus. They commissioned a professional agency to do a survey of 1000 individuals living in the city in March 2020 and obtained the following results:
Support of OHA Self-Isolation Instructions
Support |
Oppose |
Total |
|
Returning travellers |
69 |
81 |
150 |
Non-travellers who had contact |
243 |
207 |
450 |
Non-travellers who didn’t have contact |
300 |
100 |
400 |
If OHA approximates the probability of supporting/opposing the self-isolation instructions of different sub-populations (travellers and non-travellers) in March 2020 based on this survey, which method of assessment is used?
Question 15 options:
Theoretical probability |
|
Empirical probability |
|
Subjective probability |
Question 16 (1 point)
Self-isolation for Coronavirus
In the context of the current pandemic situation, the Ottawa Health Agency (OHA) was interested to know how Ottawa residents support their recommended self-isolation instructions related to the novel Coronavirus. They commissioned a professional agency to do a survey of 1000 individuals living in the city in March 2020 and obtained the following results:
Support of OHA Self-Isolation Instructions
Support |
Oppose |
Total |
|
Returning travellers |
69 |
81 |
150 |
Non-travellers who had contact |
243 |
207 |
450 |
Non-travellers who didn’t have contact |
300 |
100 |
400 |
What is the appropriate statistic for assessing the support for OHA recommended self-isolation instructions related to novel Coronavirus?
13.
The population of interest is,
Ottawa residents in March 2020
14.
OHA was interested to know how Ottawa residents support their
recommended self-isolation instructions related to the novel
Coronavirus.
The purpose of this exercise is,
Inferring information about a population from information about a
sample
15.
This is an empirical probability which is what actually happens
when we try it out.
Empirical probability
16.
Total number of respondents who support = 69 + 243 + 300 =
612
The appropriate statistic for assessing the support for OHA
recommended self-isolation instructions related to novel
Coronavirus is sample proportion of support for OHA recommended
self-isolation
Sample proportion, p = 612 / 1000 = 0.612
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