Question

In C++ code. Given an array with 35 integers, print out only those numbers that occur more than once. The 35 integers must be read from a txt file (using fstream) or randomly generated (No user input).

Answer 1

C++ CODE:

#include<iostream>
#include<ctime>
#include<cstdlib>

using namespace std;

int main()
{
   //array to store the 35 integers
   int arr[35];
   int i,j;
  
   //seed for random number
   srand(time(0));
  
   //generating 35 numbers from 1 to 100
   for(i=0;i<35;i++)
   {
   arr[i]=rand() % 100 + 1;

   }
   //printing the repeated numbers in the array
   cout<<"The repeated numbers in the array are: "<<endl;
   for(i = 0; i < 35; i++)
        for(j = i + 1; j < 35; j++)
        if(arr[i] == arr[j])
            cout<<arr[i]<<endl ;
  
   return 0;
}

SCREENSHOT FOR OUTPUT: