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A wire carries a current of 13.0 A in a direction that makes an angle of...

A wire carries a current of 13.0 A in a direction that makes an angle of 30.0° with the direction of a magnetic field of strength 0.400 T. Find the magnetic force on a 6.00 m length of the wire.
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Answer #1

given that current carrying by the wire is i=13.0A

magnetic field strength B=0.400T

angle between i and B is ?=30 degree

length of the wire is l=6.00m

magnetic force F=Bilsin?

                        =0.400*13.0*6*sin30

                        =15.6 N

I hope help you !!

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