Question

Write a function that accepts an int array and the array’s size as arguments. The function should create a copy of the array, except that the element values should be reversed in the copy. The function should return a pointer to the new array. Demonstrate the function by using it in a main program that reads an integer N (that is not more than 50) from standard input and then reads N integers from a file named data into an array. The program then passes the array to the your reverse array function, and prints the values of the new reversed array on standard output, one value per line. You may assume that the file data has at least N values. Prompts And Output Labels. There are no prompts for the integer and no labels for the reversed array that is printed out. Input Validation. If the integer read in from standard input exceeds 50 or is less than 0 the program terminates silently.

Answer 1

Note: Could you plz go through this code and let me know if u need any changes in this.Thank You
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Where we have to paste the input file in DEV C++ ??

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// nosData.txt (Input file)

45
56
67
78
89
99
88
77
66
55
44
33
22
11
17
73
39
98

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#include <fstream>
#include <iostream>

using namespace std;

int * expandArray(int arr[],int N);
int main() {
   // Declaring constant
   const int SIZE=50;
  
   // declaring variables
   string fielname="nosData.txt";
   int N;
   ifstream dataIn;
  
   //Getting the input entered by the user
   cout<<"Enter N :";
   cin>>N;
   if(N<0 || N>50)
   {
       return 1;
   }
   else
   {
       // opening the input file
       dataIn.open(fielname.c_str());
       int arr[N];
      
       /* reading the values from the file and
       * populate those values into an array
       */
       for(int i=0;i<N;i++)
       {
           dataIn>>arr[i];
       }
      
       // closing the input file
       dataIn.close();
      
       // calling the function
       int *nos=expandArray(arr,N);
      
       //Displaying the array
       cout<<"\nDisplaying Array Elements :"<<endl;
       for(int i=0;i<2*N;i++)
       {
           cout<<nos[i]<<endl;
       }
   }
  
   return 0;
}

// this function will double the array
int * expandArray(int arr[],int N)
{
   int *nos=new int[2*N];
   for(int i=0;i<2*N;i++)
   {
       nos[i]=0;
   }
   for(int i=0;i<N;i++)
   {
       nos[i]=arr[i];
   }
   return nos;
}

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Output:

===================== Thank You