Question

The components ? and ? of the velocity of a particle are: ?? = (2 ?...

The components ? and ? of the velocity of a particle are:
?? = (2 ? + 4) f / s ?? = (8 ⁄ ?) f / s (feet/sec)
Initially the particle is in the coordinates ? = 1 and ? = 0.
Determine the position, magnitude of velocity, and magnitude of acceleration of the
particle when t = 2 s.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
.The x and y components of the velocity of a particle are: vx = (2 t...
.The x and y components of the velocity of a particle are: vx = (2 t + 4) p / s vy = (8 ⁄ y) p / s Initially, the particle is located at the coordinates x = 1 and y = 0. Determine the position, the magnitude of the velocity and the magnitude of the particle's acceleration when t = 2 s.
The x and y components of the velocity of a particle are Vx=(2t + 4)ft/s &...
The x and y components of the velocity of a particle are Vx=(2t + 4)ft/s & Vy=(8/y)ft/s. Initially, the particle if found at coordinates x=1 and y=0. Determine the position, magnitude of velocity, and magnitude of the acceleration of the particle when t = 2s
1-The velocity of a particle is v = { 6 i + ( 28 - 2...
1-The velocity of a particle is v = { 6 i + ( 28 - 2 t ) j } m/s, where t is in seconds. If r=0 when t=0, determine particle displacement during time interval t = 3 s to t = 8 s in the y direction. 2-A particle, originally at rest and located at point (1 ft, 4 ft, 5 ft), is subjected to an acceleration of a={ 3 t i + 17 t2k} ft/s. Determine magnitude...
the position of a particle when t=0 is 9.0m and its velocity is 3.0 m/s. from...
the position of a particle when t=0 is 9.0m and its velocity is 3.0 m/s. from t=0 to t=3.5s the acceleration of a particle is a= 8 + 6t + 3t^2 + t^3 m/s^2 . From t=3.5s until it comes to rest, its acceleration is a= -8 m/s^2 . Determine the total travel time and the total distance.
A particle travels along the path defined by the parabola y=0.2x^2. If the component of velocity...
A particle travels along the path defined by the parabola y=0.2x^2. If the component of velocity along t he x axis is Vx=(2.9t)ft/s, where t is in seconds. determine the magnitude of the particle's acceleration when t = 1s. when t = 0 , x =0 and y = 0.
If the acceleration of a particle is given by a(t)=2t-1 and the velocity and position at...
If the acceleration of a particle is given by a(t)=2t-1 and the velocity and position at time t=0 are v(0)=0 and S(0)=2. 1. Find a formula for the velocity v(t) at time t. 2. Find a formula for the position S(t) at time t. 3. Find the total distance traveled by the particle on the interval [0,3].
A particle moves according to a law of motion s = f(t), t ≥ 0, where...
A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = t3 − 9t2 + 15t (a) Find the velocity at time t. v(t) =      (b) What is the velocity after 4 s? v(4) =  ft/s (c) When is the particle at rest? t =  s (smaller value) t =  s (larger value) (d) When is the particle moving in the positive direction? (Enter your answer...
The velocity of a particle moving along the x-axis varies with time according to v(t) =...
The velocity of a particle moving along the x-axis varies with time according to v(t) = A + Bt−1, where A = 7 m/s, B = 0.33 m, and 1.0 s ≤ t ≤ 8.0 s. Determine the acceleration (in m/s2) and position (in m) of the particle at t = 2.6 s and t = 5.6 s. Assume that x(t = 1 s) = 0. t = 2.6 s acceleration  m/s2 position  m ? t = 5.6 s acceleration  m/s2   position  m ?
A) A particle starts from the origin with velocity 5 ?̂m/s at t = 0 and...
A) A particle starts from the origin with velocity 5 ?̂m/s at t = 0 and moves in the xy plane with a varying acceleration given by ?⃗ = (2? ?̂+ 6√? ?̂), where ?⃗ is in meters per second squared and t is in seconds. i) Determine the velocity of the particle as a function of time. ii) Determine the position of the particle as a function of time. (Explanation please )
[6:10 p.m., 2020-04-17] Bhavya Pipalia: The velocity of a particle constrained to travel along a straight...
[6:10 p.m., 2020-04-17] Bhavya Pipalia: The velocity of a particle constrained to travel along a straight path is given by v(t) = 48 – 16t m/s, where t is in seconds. The particle is located at a position of 28 m at t = 0 s. a) Determine the position, velocity and acceleration of the particle at t = 2 s. b) What is the total distance travelled by the particle in the first 5 s of motion? c) What...