Question

The components ? and ? of the velocity of a particle are:

?? = (2 ? + 4) f / s ?? = (8 ⁄ ?) f / s (feet/sec)

Initially the particle is in the coordinates ? = 1 and ? = 0.

Determine the position, magnitude of velocity, and magnitude of
acceleration of the

particle when t = 2 s.

Answer #1

.The x and y components of the velocity of a particle are: vx =
(2 t + 4) p / s vy = (8 ⁄ y) p / s Initially, the particle is
located at the coordinates x = 1 and y = 0. Determine the position,
the magnitude of the velocity and the magnitude of the particle's
acceleration when t = 2 s.

The x and y components of the velocity of a particle are
Vx=(2t + 4)ft/s &
Vy=(8/y)ft/s. Initially, the particle if found at
coordinates x=1 and y=0.
Determine the position, magnitude of velocity, and magnitude of
the acceleration of the particle when t = 2s

1-The velocity of a particle is v = { 6 i + (
28 - 2 t ) j } m/s, where t is in seconds. If r=0
when t=0, determine particle displacement during time interval t =
3 s to t = 8 s in the y direction.
2-A particle, originally at rest and located at point (1 ft, 4
ft, 5 ft), is subjected to an acceleration of a={ 3 t
i + 17 t2k} ft/s.
Determine magnitude...

the position of a particle when t=0 is 9.0m and its velocity is
3.0 m/s. from t=0 to t=3.5s the acceleration of a particle is a= 8
+ 6t + 3t^2 + t^3 m/s^2 . From t=3.5s until it comes to rest, its
acceleration is a= -8 m/s^2 . Determine the total travel time and
the total distance.

A particle travels along the path defined by the parabola
y=0.2x^2. If the component of velocity along t he x axis is
Vx=(2.9t)ft/s, where t is in seconds. determine the magnitude of
the particle's acceleration when t = 1s. when t = 0 , x =0 and y =
0.

If the acceleration of a particle is given by a(t)=2t-1 and the
velocity and position at time t=0 are v(0)=0 and S(0)=2.
1. Find a formula for the velocity v(t) at time t.
2. Find a formula for the position S(t) at time t.
3. Find the total distance traveled by the particle on the
interval [0,3].

The velocity of a particle moving along the x-axis
varies with time according to
v(t) = A +
Bt−1,
where
A = 7 m/s,
B = 0.33 m,
and
1.0 s ≤ t ≤ 8.0 s.
Determine the acceleration (in m/s2) and position (in
m) of the particle at
t = 2.6 s
and
t = 5.6 s.
Assume that
x(t = 1 s) = 0.
t = 2.6 s
acceleration m/s2 position m
?
t = 5.6 s
acceleration m/s2
position m ?

A) A particle starts from the origin with velocity 5 ?̂m/s at t
= 0 and moves in the xy plane with a varying acceleration given by
?⃗ = (2? ?̂+ 6√? ?̂), where ?⃗ is in meters per second squared and
t is in seconds.
i) Determine the velocity of the particle as a function of
time.
ii) Determine the position of the particle as a function of
time.
(Explanation please )

[6:10 p.m., 2020-04-17] Bhavya Pipalia: The velocity of a
particle constrained to travel along a straight path is given by
v(t) = 48 – 16t m/s, where t
is in seconds. The particle is located at a position of 28 m at t =
0 s.
a) Determine the position, velocity and acceleration of the
particle at t = 2 s.
b) What is the total distance travelled by the particle in the
first 5 s of motion?
c) What...

A fish swimming in a horizontal plane has a velocity vo=(4i+j)
m/sec at a point in the ocean whose position vector is
r0=(10i-4j)m. After the fish swims with constant acceleration for
20 sec, its velocity is v=(20i-5j) m/s. Find 1.The components of
the acceleration.2.The direction of the acceleration with respect
to the x-axis.3.The coordinates of the fish at t=25 sec and its
direction of motion.

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