Question

Will water in a paraffin wax capillary tube inserted vertically in a reservoir of water attain...

Will water in a paraffin wax capillary tube inserted vertically in a reservoir of water attain a height in the tube greater than or less than that height in the reservoir, and why ?

Homework Answers

Answer #1

Hope it helps.

Paraffin wax is the most popular water repellent .When paraffin wax capillary tube is inserted vertically in the water reservoir then the water level in the tube is less than the height of water level in the reservoir.

This is because of the fact that water is polar in nature and paraffin wax is non polar. So there will be weak force of adhesion (i.e force between two different molecules) between water and the wall of paraffin wax tube . Due to weak adhesion force the water level falls and can't able to rise in the paraffin wax tube.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
An open, clean glass tube ( θ=0°) is inserted vertically into a pan of water (see...
An open, clean glass tube ( θ=0°) is inserted vertically into a pan of water (see the Video). What tube diameter, d (In ft), is needed if the water level in the tube is to rise 5 tube diameter's (due to surface tension)?
A tube is placed vertically in a breaker of salt water with specific gravity of 1.15....
A tube is placed vertically in a breaker of salt water with specific gravity of 1.15. The inter facial tension between air and water is 32 m N/m and contact angle degree is 30 degree. Calculate: 1) capillary pressure in psi if tube diameter is 0.0004 cm 2) capillary rise in ft 3) radius in inches of largest pore if displacement pressure is 25 kpa.
If the capillary rise in glass tube of 22 mm diameter is 5.6 mm when immersed...
If the capillary rise in glass tube of 22 mm diameter is 5.6 mm when immersed vertically in water the surface tension σ is 72.3 N/mm, calculate the angle of contact. If the same tube is immersed in mercury that has 13.6 specific gravity and its surface tension σ is 510 N/mm, calculate the capillary rise in mm if the angle of contact is 136 o.
The experiment assumes that when bubbles no longer emerge from the tube into the reservoir, the...
The experiment assumes that when bubbles no longer emerge from the tube into the reservoir, the volume of air is equal to the total volume of the experiment chamber and the temperature of the air is equal to the temperature of the boiling water. Explain why these are reasonable assumptions? Be specific.
Mercury is poured into a U-tube as shown in Figure a. The left arm of the...
Mercury is poured into a U-tube as shown in Figure a. The left arm of the tube has cross-sectional area A1 of 11.0 cm2, and the right arm has a cross-sectional area A2 of 4.90 cm2. One hundred grams of water are then poured into the right arm as shown in Figure b. Figure (a) shows a U-shaped tube filled with mercury. Both arms of the U-shaped tube are vertical. The left arm with cross-sectional area A1 is wider than...
Procedure Reaction 1: Dissolving the Copper 1. Obtain a clean, dry, glass centrifuge tube. 2. Place...
Procedure Reaction 1: Dissolving the Copper 1. Obtain a clean, dry, glass centrifuge tube. 2. Place a piece of copper wire in a weighing paper, determine the mass of the wire and place it in the centrifuge tube. The copper wire should weigh less than 0.0200 grams. 3. In a fume hood, add seven drops of concentrated nitric acid to the reaction tube so that the copper metal dissolves completely. Describe your observations in the lab report. (Caution, Concentrated nitric...
In LUMINOL SYNTHESIS, why is hot water added after mixture is cooled to 100 degrees C.?...
In LUMINOL SYNTHESIS, why is hot water added after mixture is cooled to 100 degrees C.? "Allow the solution to reach a temperature of ~190 o C and start a timer. The temperature of the reaction must be held between 190-200 o C for two minutes to obtain optimum yield. (Put one person in charge of carefully monitoring the time and temperature.) The easiest way to achieve this is to partially remove the test tube from the sand-bath when the...
1. The three tanks shown above are filled with water to an equal depth. All the...
1. The three tanks shown above are filled with water to an equal depth. All the tanks have an equal height. Tank A has the least surface area at the bottom, tank B has the greatest and tank C has the middle area at the bottom. (Select T-True, F-False, G-Greater than, L-Less than, E-Equal to. If the first is F the second L and the rest G, enter FLGGGG). A) The total force exerted by the water on the bottom...
Some of Hirschhorn et al.’s results from administering solutions with varying concentration of glucose are shown...
Some of Hirschhorn et al.’s results from administering solutions with varying concentration of glucose are shown in Figure 5. Figure 5. Effect of increasing concentrations of glucose in perfusion solutions on net stool output rate. Figure developed from data in Hirschhorn et al., 1968. Part H - Effect of added glucose on stool output in cholera Which statement best explains the effect of increasing glucose concentration in the perfusion solution on net stool output rate? Glucose had no effect because...
Diffusion of gases across a permeable membrane 1. How long did it take the O2 levels...
Diffusion of gases across a permeable membrane 1. How long did it take the O2 levels to become about equal outside and inside the cell? What happened to those levels after they became about equal over the additional 10 seconds? Why did this happen? My answer: It took 6 seconds to become equal. After they became about equal over the additional 10 seconds they fluctuate back and forth as equal equilibrium is achieved. 2.Cell use O2 and produce CO2 as...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT