Question

A hydraulic jump is formed in a trapezoidal channel of 2.0-m bed width, 1:1 side slope, and carrying a discharge of 6.0 m3/s. The initial and final depths of the jump are 0.5m and 2.0m, respectively. Concrete blocks are placed to stabilize the jump. Cf = 0.6. Construct the M-y diagram for the channel section. Find the critical depth.

Answer #1

M vs Y Curve for given channel (M on Y-axis and y on X-axis)

A concrete, trapezoidal channel with a 5-m bottom width and side
slopes of 1:1 (H:V) discharges 35 m3/sec. The bottom slope of the
channel is 0.004. A dam is placed across the channel and raises the
water level to a depth of 3.4 m. determine the channel and flow
classification (e.g., M-2, S-1) upstream of the dam and explain
your supporting logic. then compute the water surface profile at
50-m intervals until you reach the hydraulic jump. Use a
spreadsheet...

Water flows in a rectangular concrete channel that is 10 m wide
and has a slope of 0.005. The depth of the uniform flow in the
channel (y1) is 450 mm and the discharge per width of
the water is 2.2 m2/s. The downstream channel is smooth,
and a hydraulic jump is forced to form in the channel by installing
a sill. Calculate:
(i) the depth and velocity of the water downstream of the
hydraulic jump;
(ii) the difference in...

A trapezoidal channel is 6 m wide and has a side slope of 0.5
horizontal: 1 vertical. If the
bed slope of the channel is 0.0004 and Manning’s n = 0.02,
find the discharge which can
make the channel a hydraulically efficient channel
section.

A discharge of 4.25 m3 /s occurs within a trapezoidal channel
with a base width of 3m, 3:1 side slopes (i.e. Z = 3), a
longitudinal bed slope of 0.0009 m/m with a Manning’s roughness
coefficient of 0.025 (i.e. sand). State the normal flow depth (yn)
critical flow depth (yc) and the Froude Number of the flowing
water.

7. A) Find the depth of water flowing through a triangular
channel having a bed slope of 1 in 3500 and side slope of 1:1, when
it carries 1.2 m3/s. Take Manning’s Coefficient N = 0.014
B) For a most economical trapezoidal section of side slope 2h: 5V,
bed slope of 1 in 2000 and C = 50. Find the rate of flow if the
bottom width of the channel is 5 m.

A trapezoidal concrete channel (n = 0.015) has side slopes of
2H:1V, a bottom width of 10.0 ft, and a longitudinal slope of
0.005.
(a) Compute the discharge rate (in cfs) and velocity (ft/s) when
the water depth is 3.0 ft.
(b) Compute normal depth and critical depth (in feet) for a
discharge rate of 300 cfs.

A trapezoidal channel has a bottom width of 5 m and side slopes
m = 2. If the flow rate is 20 m3/s, what is critical depth?

1.
A trapezoidal channel carrying 11.5 m3/s clear water is built with
concrete (no erodible) channel having a slope of 0.0016 and n=
0.025. Proportion the section dimensions. Use best hydraulic
section approach

In a trapezoidal channel with a constant width of b=3 m. and
side slopes of 1:3 (1 vertical, 3 horizontal) and discharge rate of
6 m3 /sec, if the maximum step upward height is z=0.5 m. not to
cause any choking, what is the water depth before and after this
maximum step upward. Draw the water surface profile and specific
energy curve (E vs y) for this flow.

Q4. A hydraulic jump occurs fort the given flow
conditions: discharge=20 m3/s, upstream channel geometry
trapezoid (upstream flow depth=100 cm, bottom width=100 cm, m=2),
downstream channel geometry rectangular (width= 500 cm). Calculate
downstream flow depth and power loss in the hydraulic jump.

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 3 hours ago

asked 3 hours ago

asked 3 hours ago

asked 3 hours ago

asked 3 hours ago

asked 3 hours ago

asked 4 hours ago