Determine the number of bonding groups for H2S. n = SubmitMy AnswersGive Up Part F Determine the number of lone pairs around the central atom for H2S. n = SubmitMy AnswersGive Up Part G Determine the number of bonding groups for PCl3. n = SubmitMy AnswersGive Up Part H Determine the number of lone pairs around the central atom for PCl3. n = SubmitMy AnswersGive Up
1) H2S
Sulphur (S) is the central metal atom. It has 6 valence electrons. It shares two of its electrons with 1 valence electron of each H atom. Thus, it has the following structure:
So, H2S has two bonding groups and the central metal atom S has two lone pairs of electrons.
2) PCl3
Here, P is the central metal atom with 5 valence electrons. It will share 3 of its electrons with the three Cl atoms. Each Cl atom has 7 valence electrons. So, it can share only one electron. Thus, the structure of PCl3 will be:
So, PCl3 will have 3 bonding groups and the central metal atom P has 1 lone pair of electrons.
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