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Given the values of ΔH∘rxn, ΔS∘rxn, and T below, determine ΔSuniv. Part A ΔH∘rxn= 115 kJ...

Given the values of ΔH∘rxn, ΔS∘rxn, and T below, determine ΔSuniv.

Part A

ΔH∘rxn= 115 kJ , ΔS∘rxn=− 263 J/K , T= 301 K .

ΔSuniv= J/K

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Part B

ΔH∘rxn=− 115 kJ , ΔS∘rxn= 263 J/K , T= 301 K .

ΔSuniv= J/K

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Part C

ΔH∘rxn=− 115 kJ , ΔS∘rxn=− 263 J/K , T= 301 K .

ΔSuniv= J/K

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Part D

ΔH∘rxn=− 115 kJ , ΔS∘rxn=− 263 J/K , T= 557 K .

Express your answer using two significant figures.

ΔSuniv= J/K

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Part E

Predict whether or not the reaction in part A will be spontaneous. (Assume that all reactants and products are in their standard states.)

Predict whether or not the reaction in part A will be spontaneous. (Assume that all reactants and products are in their standard states.)
spontaneous
nonspontaneous

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Part F

Predict whether or not the reaction in part B will be spontaneous. (Assume that all reactants and products are in their standard states.)

Predict whether or not the reaction in part B will be spontaneous. (Assume that all reactants and products are in their standard states.)
spontaneous
nonspontaneous

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Part G

Predict whether or not the reaction in part C will be spontaneous. (Assume that all reactants and products are in their standard states.)

Predict whether or not the reaction in part C will be spontaneous. (Assume that all reactants and products are in their standard states.)
spontaneous
nonspontaneous

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Part H

Predict whether or not the reaction in part D will be spontaneous. (Assume that all reactants and products are in their standard states.)

Predict whether or not the reaction in part D will be spontaneous. (Assume that all reactants and products are in their standard states.)
spontaneous
nonspontaneous

Homework Answers

Answer #1

In order to compare equilibirum vs. spontaneous/nonspontaneous reactions, we better use a criteria.

Recall that if dSuniverse > 0, this is spontaneous, if dSuniverse = 0, this is inequilbirium and if dSuniverse < 0 this is never possible.

Then, recall that

dSuniverse = dSsurroundings + dSsystem

dSsystem = Sproducts - Sreactants

dSsurroundings = Qsurroundings/T = -dHsystem/T

therefore

dSystem =  -dHsystem/T + dSsystem

then

A) dS = (-115*1000/301) + -263 , = -645 J/K

B) dS = (115*1000/301) + 263 = + 645 J/K

C) dS = 115*1000/301 -263; = 119 J/K

D) dS = 115*1000/557 - 263= -56.53 J/K

if dS > 0, this is spontaneous

for A , nonspontaneous

for B spontaneous

for C spontaneous

for D nonspontaneous

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