Question

Part A Determine the number of bonding groups for CH2Cl2. n = SubmitMy AnswersGive Up Part B Determine the number of lone pairs around the central atom for CH2Cl2. n = SubmitMy AnswersGive Up Part C Determine the number of bonding groups for SBr2. n = SubmitMy AnswersGive Up Part D Determine the number of lone pairs around the central atom for SBr2. n = SubmitMy AnswersGive Up Part E Determine the number of bonding groups for H2S. n = SubmitMy AnswersGive Up Part F Determine the number of lone pairs around the central atom for H2S. n = SubmitMy AnswersGive Up Part G Determine the number of bonding groups for PCl3. n = SubmitMy AnswersGive Up Part H Determine the number of lone pairs around the central atom for PCl3. n = SubmitMy AnswersGive Up

Answer 1

part A) In CH2Cl2 ,C is the central atom with four valence electrons (1s2 2s2 2p2) shared with two Cl and two H ,forming 4 bonds around the center ,C

It has 4 bonding groups,tetrahedral electron geometry,tetrahedral molecular geometry

part B) No lone pair around central carbon,as all valence electrons are shared, with two Cl and two H ,forming 4 bonds

part C:

SBr2

S,sulfur is the central atom in this molecule with electron configuration: 1S2 2S2 2p6 3s2 3p4

Thus, it has 6 valence electrons and requires two more electron to complete its octet.Its valency is 2

It shares two valence electrons with Br forming two bonding pairs, and four electrons are non-bonding (two lone pairs)

bonding pair =2

part D) lone pairs=2

tetrahedral electron pair geometry ,bent molecular geometry