Question

Part A - 3.25a

CoSO4⋅7H2O

Spell out the full name of the compound.

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Part B - 3.25d

potassium carbonate dihydrate

Express your answer as a chemical formula.

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Part C - 3.26b

BeCl2⋅2H2O

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Part D - 3.26c

chromium(III) phosphate trihydrate

Express your answer as a chemical formula.

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Part E - 3.27c

SiCl4

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Part F - 3.27d

N4Se4

Spell out the full name of the compound.

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Part G - 3.28b

SO2

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Part H - 3.28c

BrF5

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Part I - 3.28d

NO

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Part J - 3.29a

phosphorus trichloride

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Part K - 3.29d

phosphorus pentafluoride

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Part L

How much of this rock (in kg) must be processed to obtain 5.1 metric tons of lead? (A metric ton is 1000 kg.)

Express your answer using two significant figures.

m =

kg

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Part M

If the oxide contains 16.99 % O by mass, what is the identity of the metal?

Express your answer as a chemical symbol.

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Answer 1

CoSO4⋅7H2O

cobalt(II) sulphate heptahydrate

part-B

potassium carbonate dihydrate

K2CO3 .2H2O

part-C

BeCl2⋅2H2O

berelium chloride dihydrate.

part-D

chromium(III) phosphate trihydrate

CrPO4.3H2O

part-E

SiClsilicon trachloride

part-F

N4Se4

selinium nitride

part-G

SO2 sulphur dioxide

part-H

BrF5

bromium pentabromide

part-I

NO

nitric oxide

part-J

phosphorus trichloride

PCl3

part-K

phosphorus pentafluoride

PF5

part-L

metric tons   = 1000kg

5.1 metric tons of lead    = 5.1*1000 kg   = 5100kg

part-K

M=100-16.99   = 83.01%

M2O = K2O

potasium