Question

Find the standard​ deviation, s, of sample data summarized in the frequency distribution table given below...

Find the standard​ deviation, s, of sample data summarized in the frequency distribution table given below by using the formula​ below, where x represents the class​ midpoint, f represents the class​ frequency, and n represents the total number of sample values.​ Also, compare the computed standard deviation to the standard deviation obtained from the original list of data​ values, 9.0. sequalsStartRoot StartFraction n left bracket Summation from nothing to nothing left parenthesis f times x squared right parenthesis right bracket minus left bracket Summation from nothing to nothing left parenthesis f times x right parenthesis right bracket squared Over n left parenthesis n minus 1 right parenthesis EndFraction EndRoot Interval 20​-29 30​-39 40​-49 50​-59 60​-69 70​-79 Frequency 1 21 40 20 8 5 Standard deviationequals 11.0 ​(Round to one decimal place as​ needed.)

Find the standard​ deviation, s, of sample data summarized in the frequency distribution table given below by using the formula​ below, where x represents the class​ midpoint, f represents the class​ frequency, and n represents the total number of sample values.​ Also, compare the computed standard deviation to the standard deviation obtained from the original list of data​ values,

9.09.0.

sequals=StartRoot StartFraction n left bracket Summation from nothing to nothing left parenthesis f times x squared right parenthesis right bracket minus left bracket Summation from nothing to nothing left parenthesis f times x right parenthesis right bracket squared Over n left parenthesis n minus 1 right parenthesis EndFraction EndRootn∑f•x2−∑(f•x)2n(n−1)

Interval

2020​-2929

3030​-3939

4040​-4949

5050​-5959

6060​-6969

7070​-7979

Frequency

11

2121

4040

2020

88

55

Standard

deviationequals=11.011.0

​(Round to one decimal place as​ needed.)

Homework Answers

Answer #1

Solution:

given that,

Class
(1)
Frequency (f)
(2)
Mid value (x)
(3)
d=x-Ah=x-5054.5*1010
A=5054.5,h=1010
(4)
fd
(5)
f*
(6)
2020 - 2029 11 2024.5 -3 -33 99
3030 - 3039 2121 3034.5 -2 -4242 8484
4040 - 4049 4040 4044.5 -1 -4040 4040
5050 - 5059 2020 5054.5 0 0 0
6060 - 6069 88 6064.5 1 88 88
7070 - 7079 55 7074.5 2 110 220
--- --- --- --- --- ---
n=8335 ----- ----- fd=-8117 f*=12931

Solution:

Sample Standard deviation


=√0.6031*1010


=0.7766*1010

=784.366

=784.4

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