Question

Calculate the reaction quotient Qp for the following redox reaction: 14H+ + Cr2O72- + 6Cl- ---->...

Calculate the reaction quotient Qp for the following redox reaction:

14H+ + Cr2O72- + 6Cl- ----> 2Cr3+ + 3Cl2 + 7H2O

The reaction mixture has pH = 0.0, [Cr2O72-] = 1.0 M, [Cl-] = 1.0 M, [Cr3+] = 0.10 M, and parital pressure of chlorine gas of 0.010 atm.

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Homework Answers

Answer #1

For the given reaction

Qc = [Cr3+]2 *[Cl2]3/[ Cl-]6*[ Cr2O72-]*[H+]14

Activity of water = 1

Given, pH = 0, then [ H+ ] = 1 ( pH = - log [ H+] )

Partial pressure of Cl2 = 0.010 atm

From ideal gas law, PV = nRT or, P = CRT ( C = n/ V)

C is concentration .

Then, [ Cl2] = P/ RT = 0.010/0.082*298 = 0.004 mol.L-1 or, M

( assuming temperature = 298 K)

Tgen, Qc = (0.10)2(0.004)3/(1.0)6*1.0*(1.0)14

=1*10-2* 64*10-9

= 6.4*10-10

Now, Qp = Qc *RTn

in the given equation , n = total number of moles of gaseous product - total number of moles of gaseous reactant.

= 3 - 0 = 3 ( only the product chlorine is gas )

So, Qp = 6.4*10-10 * ( 0.082*298)3

= 6.4*10-10*1.459*104

= 9.338*10-6

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