Question

Calculate the pH of the cathode compartment for the following reaction given ℰcell = 3.01 V...

Calculate the pH of the cathode compartment for the following reaction given ℰcell = 3.01 V when [Cr3+ ] = 0.15 M, [Al3+ ] = 0.26 M, and [Cr2O72− ] = 0.65 M.

2 Al(s) + Cr2O72−(aq) + 14 H +(aq) → 2 Al3+(aq) + 2 Cr3+(aq) + 7 H2O(l)

pH=?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
7. Determine Eo for the following reaction, using the given standard reduction potentials: Cu(s) + Fe2+(aq)...
7. Determine Eo for the following reaction, using the given standard reduction potentials: Cu(s) + Fe2+(aq) → Cu+(aq) + Fe(s) Eo for Fe2+(aq) = -0.44 V Eo for Cu+(aq) = 0.52 V 8. Consider the following half-reactions. Which of these is the strongest oxidizing agent listed here? I2(s) + 2 e- → 2 I-(aq) Eo = 0.53 V S2O82-(aq) + 2 e- → 2 SO42-(aq) Eo = 2.01 V Cr2O72-(aq) + 14 H+ + 6 e- → Cr3+(aq) + 7...
Consider the following half-reactions. Which of these is the strongest reducing agent listed here? I2(s) +...
Consider the following half-reactions. Which of these is the strongest reducing agent listed here? I2(s) + 2 e- → 2 I-(aq) Eo = 0.53 V S2O82-(aq) + 2 e- → 2 SO42-(aq) Eo = 2.01 V Cr2O72-(aq) + 14 H+ + 6 e- → Cr3+(aq) + 7 H2O(l) Eo = 1.33 V 1. I2(s) 2. I-(aq) 3. S2O82-(aq) 4. SO42- 5. Cr2O72- 6. Cr3+(aq)
1. Consider the reaction: Cr2O72- (aq) + 14 H+ (aq) + 6 Fe2+ (aq) >>> 2...
1. Consider the reaction: Cr2O72- (aq) + 14 H+ (aq) + 6 Fe2+ (aq) >>> 2 Cr3+ (aq) + 6 Fe3+ (aq) + 7 H2O (l) In the lab, it is found that 19.30 mL of K2Cr2O7 solution is needed to react with 25.00 mL of 0.4000 M Fe2+ (aq) solution, what is the molarity of the potassium dichromate solution?
1) For a galvanic cell that uses the following two half-reactions, Cr2O72-(aq) + 14 H+(aq) +...
1) For a galvanic cell that uses the following two half-reactions, Cr2O72-(aq) + 14 H+(aq) + 6 e- → 2 Cr3+(aq) + 7 H2O(l) Pb(s) → Pb2+(aq) + 2 e how many moles of Pb(s) are oxidized by one mole of Cr2O72-? A) 6 B) 2 C) 1 D) 3 2) What species is oxidized in the reaction: CuSO4(aq) + Mg(s) →MgSO4(aq) + Cu(s)? A) MgSO4 (aq) B ) M g (s) C ) C u S O 4 (aq)...
Standard Reduction (Electrode) Potentials at 25 oC Half-Cell Reaction Eo (volts) Standard Reduction (Electrode) Potentials at...
Standard Reduction (Electrode) Potentials at 25 oC Half-Cell Reaction Eo (volts) Standard Reduction (Electrode) Potentials at 25 oC Half-Cell Reaction Eo (volts) F2(g) + 2 e- 2 F-(aq) 2.87 Ce4+(aq) + e- Ce3+(aq) 1.61 MnO4-(aq) + 8 H+(aq) + 5 e- Mn2+(aq) + 4 H2O(l) 1.51 Cl2(g) + 2 e- 2 Cl-(aq) 1.36 Cr2O72-(aq) + 14 H+(aq) + 6 e- 2 Cr3+(aq) + 7 H2O(l) 1.33 O2(g) + 4 H+(aq) + 4 e- 2 H2O(l) 1.229 Br2(l) + 2 e-...
Standard Reduction (Electrode) Potentials at 25 oC Half-Cell Reaction Eo (volts) Standard Reduction (Electrode) Potentials at...
Standard Reduction (Electrode) Potentials at 25 oC Half-Cell Reaction Eo (volts) Standard Reduction (Electrode) Potentials at 25 oC Half-Cell Reaction Eo (volts) F2(g) + 2 e- 2 F-(aq) 2.87 Ce4+(aq) + e- Ce3+(aq) 1.61 MnO4-(aq) + 8 H+(aq) + 5 e- Mn2+(aq) + 4 H2O(l) 1.51 Cl2(g) + 2 e- 2 Cl-(aq) 1.36 Cr2O72-(aq) + 14 H+(aq) + 6 e- 2 Cr3+(aq) + 7 H2O(l) 1.33 O2(g) + 4 H+(aq) + 4 e- 2 H2O(l) 1.229 Br2(l) + 2 e-...
Electrochemistry Given the following cell diagram C(gr)|SO4-2(aq), SO3-2(aq), OH-(aq)||MnO4-(aq),OH-(aq)|MnO2(s)|C(gr) Provide: a)The anode reaction, the cathode reaction,...
Electrochemistry Given the following cell diagram C(gr)|SO4-2(aq), SO3-2(aq), OH-(aq)||MnO4-(aq),OH-(aq)|MnO2(s)|C(gr) Provide: a)The anode reaction, the cathode reaction, the #of e- transferred, overall balanced equation, the Q expression. 2. Given the following skeletal reaction (assume acidic conditions): OBr-(aq)+Cr3+(aq)-->CrO4-2(aq)+Br(l) Provide: the anode reaction, the cathode reaction, the overall balanced equation, the number of e- transferred, the Q expression, the cell diagram
Calculate the cell potential for the voltaic cell based on the following half reactions at T...
Calculate the cell potential for the voltaic cell based on the following half reactions at T = 25ºC: Cr3+(aq) + 3e- → Cr(s) Eº = - 0.74 V TiO2+(aq) + 2H+ (aq) + 1e- → Ti3+(aq) + H2O(l) Eº = + 0.10 V Where, [Cr3+] = 1.0 x 10-4 M, [TiO2+] = 1.0 x 10-1 M, [H+] = 1.0 M, [Ti3+] = 5.0 x 10-2 M.
A 4.979 g sample containing the mineral tellurite was dissolved and then treated with 50.00 mL...
A 4.979 g sample containing the mineral tellurite was dissolved and then treated with 50.00 mL of 0.03187 M K2Cr2O7. Upon completion of the reaction, the excess Cr2O72- required 37.58 mL of 0.1197 M Fe2+ solution. Calculate the percentage by mass of TeO2 (FM 159.60) in the sample. The reactions are 3 TeO2 + Cr2O72- + 8 H+ → 3 H2TeO4 + 2 Cr3+ + H2O Cr2O72- + 6 Fe2+ + 14 H+ → 2 Cr3+ + 6 Fe3+ +...
A voltaic cell utilizes the following reaction: 4Fe2+(aq)+O2(g)+4H+(aq)→4Fe3+(aq)+2H2O(l). A) What is the emf of this cell...
A voltaic cell utilizes the following reaction: 4Fe2+(aq)+O2(g)+4H+(aq)→4Fe3+(aq)+2H2O(l). A) What is the emf of this cell when [Fe2+]= 2.0 M , [Fe3+]= 1.0×10−2 M , PO2=0.60 atm and the pH of the solution in the cathode compartment is 3.7? Express your answer using two significant figures.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT