Question

Part of this prevous answer was wrong, you cannot have 2 theoritical yields.

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Plastic cup A

Mass of cup, water, and stirrer: 57.02g

Mass of sodium bicarbonate: 1.05g

Mass of citric acid: 0.77g

Total mass: 59.02

Mass of cup, the solution, and stirrer after reaction: 58.53g

Difference: 0.49g

H₃C₆H₅O₇(aq) + 3NaHCO₃(aq) --->Na₃C₆H₅O₇(aq) + 3H₂O(l) + 3CO₂(g)

1) Show that the equivalence amount of citric acid for 1.00 g of sodium bicarbonate is 0.76 g

2) Calculate the theoretical yield of carbon dioxide from 1.00g of sodium bicarbonate

3. Actual yield should be 0.49 which I got in above

4) Calculate the percentage yield in the plastic cup A experimemt

e

Answer 1

H3C6H5O7(aq) + 3NaHCO3(aq) --->Na3C6H5O7(aq) + 3H2O(l) + 3CO2(g)

1) Amount of citric acid required for 0.76 g NaHCO3 =

=

=0.76 g

It is shown that equivalence amount of citric acid for 1.00 g of sodium bicarbonate is 0.76 g

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2) Theoriitical yield of CO2 =

=0.52 g CO₂

Mass of CO₂ produced from 1.0 g NaHCO₃ = 0.52 g

3) actual yield = 0.49 g

4)

Percentage yield = 94.2%