Question

Calculate the temperature, in K, of 2.20 moles of gas occupying 3.70 L at 3.12 atm.

Answer 1

To calculate the temperature of the gas, we assume that the gas is an ideal gas. For ideal gas we can write

PV=nRT..............(1)

where P is pressure, V is volume, n is number of moles, R is universal gas constant and T is temperature in Kelvin.

We can rearrange equation 1 as

T = PV/nR

Given P = 3.12 atm, V = 3.70 L n= 2.20 moles. To make sure that the units are consistent we will use the value of R = 0.0821 atm.L/mol.K.

So T = (3.12 atm*3.70L)/(2.20 mol * 0.0821 atm.L/mol.K) = 63.913 K 64 K