A sample of a compound weighing 83.5 g contains 33.4 g of sulfur. The rest is oxygen. What is the empirical formula?
A sample of a compound weighing 83.5 g contains 33.4 g of sulfur. The rest is oxygen.
therefore in 83.5 g of compound mass of Oxygen = 83.5-33.4 gm = 50.1 gm
moles of sulphr = 33.4/32 = 1.04375 moles
moles of oxygen = 50.1/16 = 3.13125 moles
ratio of amount of sulphur and oxygen = 1.04375/3.13215 =almost 1/3 or 1:3
Now , The empirical formula is the simplest formula for a compound. A molecular formula is the same as or a multiple of the empirical formula, and is based on the actual number of atoms of each type in the compound. For example, if the empirical formula of a compound is C3H8 , its molecular formula may be C3H8 , C6H16 , etc.
so , here ratio of sulphur and oxygen is 1:3
so empirical formula will be SO3...answer
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