Question

Calculate the volume (in mL) of CO2 at 25 oC and 1.0 atm dissolved in a...

Calculate the volume (in mL) of CO2 at 25 oC and 1.0 atm dissolved in a 10.0 L bucket of rainwater that has a pH of 4.5.

I know the answer is 580, I just don't know how to solve it. Please help!

Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

The author considered that the pH of rainwater is only due to H2CO3 (dissolved CO2)!.

H2CO3(aq) ⇌ H+(aq) + HCO3–(aq)         Ka1= 4.3x10-7 (ignore the second step).

At pH = 4.5     [H+] = 10-4.5 = 3.2x10-5

Calculate as usual:

[H+] = [HCO3–]

[H+] = (Ka . CH2CO3)1/2

(3.2x10-5 )2 / 4.3x10-7 = CH2CO3

CH2CO3 = 2.32x10-3 mol/Lwater

2.4x10-3 mol CO2/Lwater x 22.4 L CO2 /mol x (298K/273K) = 0.058 L CO2 /L water

58 mL CO2 x 10 L = 580 mL CO2

(the molar volume 22.4 L at std cond was corected for 298 K)

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate the volume (in mL) of CO2 at 25 oC and 1.0 atm dissolved in a...
Calculate the volume (in mL) of CO2 at 25 oC and 1.0 atm dissolved in a 10.0 L bucket of rainwater that has pH of 4.5. The answer is supposed to be 580 but I keep getting 568. Please Help!
3. Calculate the volume occupied by 88.2 g of CO2 at 0.955 atm and 25°C. R...
3. Calculate the volume occupied by 88.2 g of CO2 at 0.955 atm and 25°C. R = 0.08206 Lxatm/Kxmol.
The concentration of CO2 in a soft drink under a pressure of 2.3 atm is 0.071...
The concentration of CO2 in a soft drink under a pressure of 2.3 atm is 0.071 M. Calculate the concentration of CO2 in a soft drink after the bottle is opened and equilibrates at the same temperature under a CO2 partial pressure of 3.0 x 10-4atm. The answer is 9.3 * 10^-6 M but I don't know how to start this problem. Pls help!
3. An athlete at high performances inhales 4.0 L of air at 1.0 atm and 298...
3. An athlete at high performances inhales 4.0 L of air at 1.0 atm and 298 K at a respiration rate of 40 breaths per minute. a. If the exhaled and inhaled air contain 15.3% and 20.9% oxygen by volume, respectively, how many moles of oxygen per minute are absorbed by the athlete’s body? b. Assume that inhaled and exhaled air contain 0.5% and 6.2% water vapor by volume, respectively. If the athlete performs for one hour, how much water...
[4] Please calculate the volume for H2 gas at 25°C and 1.00 atm that will college...
[4] Please calculate the volume for H2 gas at 25°C and 1.00 atm that will college at the cathode when an (aq) solution of Na2SO4 is electrolyzed for 2.00 hours with a 10.0-amp current.
Propagation of error: Determine the uncertainty in the concentration if you dissolved 0.500 ± 0.001 g...
Propagation of error: Determine the uncertainty in the concentration if you dissolved 0.500 ± 0.001 g of NaCl in the average glass pipet volume determined above. Use the SD of the volume and propagation of error rules to perform this calculation. Report the concentration and uncertainty both in terms of Molarity and ppm for Na+ Average is 24.9 mL and SD is 0.030 I get 0.34 +/- 0.002 for molarity but I don't know how to solve for ppm, Please...
At 295 K and 1.00 atm, assume that 22.0 mL of NO gas reacts with 22.0...
At 295 K and 1.00 atm, assume that 22.0 mL of NO gas reacts with 22.0 mL of oxygen gas and excess water to produce gaseous nitric acid according to the following equation: 2NO(g)+3/2O2(g)+H2O(l)----->2HNO3(g) If all of the nitric acid produced by this reaction is collected and then dissolved into 15.0 mL of water, what would be the pH of the resulting solution? (Hint: before you begin, think about which reactant is the limiting reagent.) Please help! If someone could...
1.) A volume of 36.7 mL of H2O is initially at 28.0 oC. A chilled glass...
1.) A volume of 36.7 mL of H2O is initially at 28.0 oC. A chilled glass marble weighing 4.00 g with a heat capacity of 3.52 J/oC is placed in the water. If the final temperature of the system is 26.4  oC , what was the initial temperature of the marble? Water has a density of 1.00 g/mL and a specific heat of 4.18 J/goC. Enter your answer numerically, to three significant figures and in terms of oC. 2.) A 2.24...
When 1.0 mole of acetic acid is diluted with water to a volume of 1.0 L...
When 1.0 mole of acetic acid is diluted with water to a volume of 1.0 L at 25 C, 0.42% of the acetic acid ionizes to form acetate ion and hydronium ion. CH3CO2H(aq) + H2O(l) = CH3CO2–(aq) + H3O+(aq) What percentage of the acid ionizes when 0.75 mole of acetic acid is diluted with water to 1.0 L at 25 C? Can you show the answer step by step so I can figure out how to do the other examples...
Sodium carbonate (2.4134 g) is dissolved in enough deionized water to give a solution with a...
Sodium carbonate (2.4134 g) is dissolved in enough deionized water to give a solution with a total volume of 250.0 mL. What is the pH of the resulting solution? Hint: For carbonic acid, pKa1 = 6.351 and pKa2 = 10.329. What is the equilibrium concentration of H2CO3 in the solution? calculate the value of alpha HCO3-. I already have the answer to the first part of the question. I just need the equilibrium concentration and value of alpha please!
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT