Question

3. Calculate the volume occupied by 88.2 g of CO2 at 0.955 atm and 25°C. R = 0.08206 Lxatm/Kxmol.

Answer 1

Molar mass of CO2 = 1*MM(C) + 2*MM(O)

= 1*12.01 + 2*16.0

= 44.01 g/mol

mass of CO2 = 88.2 g

we have below equation to be used:

number of mol of CO2,

n = mass of CO2/molar mass of CO2

=(88.2 g)/(44.01 g/mol)

= 2.004 mol

we have:

P = 0.955 atm

n = 2.0041 mol

T = 25.0 oC

= (25.0+273) K

= 298 K

we have below equation to be used:

P * V = n*R*T

0.955 atm * V = 2.0041 mol* 0.08206 atm.L/mol.K * 298 K

V = 51.3 L

Answer: 51.3 L