Question

Ammonia is prepared industrially by the reaction: Let = represent the symbol for chemical equilibrium :N2(g)...

Ammonia is prepared industrially by the reaction: Let = represent the symbol for chemical equilibrium :N2(g) + 3H2(g) = 2NH3(g) For the reaction, ΔH° = –92.2 kJ and K (at 25°C. = 4.0 ×108. What is the direction of the equilibrium position when the temperature of the reaction is increased to 500°C? Explain your answer.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
N2 (g) + 3H2 (g) → 2NH3(g) ΔH = -92.2 kJ What mass of ammonia is...
N2 (g) + 3H2 (g) → 2NH3(g) ΔH = -92.2 kJ What mass of ammonia is theoretically produced if the above reaction released 183 kJ of heat? Please show work
1. The equilibrium constant, Kp, for the following reaction is 4.55×10-5 at 723 K. N2(g) +...
1. The equilibrium constant, Kp, for the following reaction is 4.55×10-5 at 723 K. N2(g) + 3H2(g) 2NH3(g) If ΔH° for this reaction is -111 kJ, what is the value of Kp at 839 K? Kp= 2. The equilibrium constant, Kp, for the following reaction is 0.110 at 298 K. NH4HS(s) NH3(g) + H2S(g) If ΔH° for this reaction is 92.7 kJ, what is the value of Kp at 393 K? Kp=
Ammonia is formed by the Haber process according to the following reaction: N2(g) + 3H2(g) ⇌...
Ammonia is formed by the Haber process according to the following reaction: N2(g) + 3H2(g) ⇌ 2NH3(g) Use the following data table to answer the questions below: Substance: ΔHf (kJ/mol) So (J/(mol*K) N2(g) 0    187.4 H2(g) 0 127.1 NH3(g) -47.3 197.6 Part 1: Using the table in the introduction, calculate the value of ΔH in units of kJ/mol. After, calculate the value of ΔS in units of J/(mol*K). Finally, cCalculate the value of ΔG in units of kJ/mol for...
Consider the following chemical equation and equilibrium constant at 25 ∘C: N2(g)+3H2(g)⇌2NH3(g) K=5.6×105 Calculate the equilibrium...
Consider the following chemical equation and equilibrium constant at 25 ∘C: N2(g)+3H2(g)⇌2NH3(g) K=5.6×105 Calculate the equilibrium constant for the following reaction at 25 ∘C: NH3(g)⇌12N2(g)+32H2(g)
In the Haber process, ammonia is synthesized from nitrogen and hydrogen: N2(g) + 3H2(g) → 2NH3(g)...
In the Haber process, ammonia is synthesized from nitrogen and hydrogen: N2(g) + 3H2(g) → 2NH3(g) ΔG° at 298 K for this reaction is -33.3 kJ/mol. The value of ΔG at 298 K for a reaction mixture that consists of 1.7 atm N2, 3.2 atm H2, and 0.85 atm NH3 is a) -139.6 b) 0.43 c) -4.63 × 103 d) -44.1 e) -1.08 × 104
Determine the equilibrium constant Kp at 25°C for the reaction: N2(g) + 3H2(g) ⇆ 2NH3(g) (G°f...
Determine the equilibrium constant Kp at 25°C for the reaction: N2(g) + 3H2(g) ⇆ 2NH3(g) (G°f (NH3(g)) = -16.6 kJ/mol)
The chemical reaction N2(g) + 3H2(g) 2NH3(g) is carried out at 400. K. Assume the partial...
The chemical reaction N2(g) + 3H2(g) 2NH3(g) is carried out at 400. K. Assume the partial pressures of N2(g), H2(g), and NH3(g) are 1.0, 4.2, and 63 atm, respectively. The value of Kp = 54 at 700. K. for this reaction. (a) Calculate the reaction free energy. (b) Indicate whether this reaction mixture is likely to form reactants, is likely to form products, or is at equilibrium.
Ammonia can also be synthesized by the reaction: 3H2(g)+N2(g)→2NH3(g) What is the theoretical yield of ammonia,...
Ammonia can also be synthesized by the reaction: 3H2(g)+N2(g)→2NH3(g) What is the theoretical yield of ammonia, in kilograms, that we can synthesize from 5.55 kg of H2 and 33.9 kg of N2?
Ammonia is produced directly from nitrogen and hydrogen by using the Haber process. The chemical reaction...
Ammonia is produced directly from nitrogen and hydrogen by using the Haber process. The chemical reaction is N2(g)+3H2(g) ---> 2NH3 (g) (a) Use bond enthalpies to estimate the enthalpy change for the reaction, and tell whether this reaction is exothermic or endothermic (b) Compare the enthalpy change you calculate in (a) to the true enthalpy change as obtained using ∆Hf° values. (∆Hf° of ammonia is -46.19 kJ/mol)
Ammonia gas, NH3 (g), can be prepared according to the equilibrium below (to be called “the...
Ammonia gas, NH3 (g), can be prepared according to the equilibrium below (to be called “the system” henceforth): N2 (g) + 3H2 (g) ⇌ 2NH3 (g) Kc = 1.2 (at 375 0 C); ΔH0 = - 92 kJ A) Please calculate Kp for this equilibrium. B) Please determine Kp for the decomposition of ammonia into its elements C) Please determine the value of Qc given [NH3] = 0.110 M, [H2] = 0.099 M, and [N2] = 10.1 M. D) Please...