Question

Consider the following chemical equation and equilibrium constant at 25 ∘C: N2(g)+3H2(g)⇌2NH3(g) K=5.6×105 Calculate the equilibrium...

Consider the following chemical equation and equilibrium constant at 25 ∘C:
N2(g)+3H2(g)⇌2NH3(g) K=5.6×105

Calculate the equilibrium constant for the following reaction at 25 ∘C:
NH3(g)⇌12N2(g)+32H2(g)

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Answer #1

For equation (1) N2(g)+3H2(g)⇌2NH3(g) Kc = 5.6×105

                2NH3(g)⇌ N2(g)+3H2(g)Kc = 1/5.6×105

For equation (2) NH3(g)⇌12N2(g)+32H2(g)K'c = ?

           Kc AND K'c RELATION IS K'c = ROOT KC.

                              i.e K'c = ROOT 1/5.6×105

                               ANSWER IS 1.3363021 × 10-3   

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