cyclo pentanone will get oxidised and give the cyclopentanone
reduction hal reaction
reduction half reaction
from the above reaction it is clear that Cr under go reduction
Cr2O72- ------> 2 Cr3+
Cr2O72- ------> 2 Cr3+ + 7 H2O
14 H+ + Cr2O72- ------> 2 Cr3+ + 7 H2O
14 H+ + Cr2O72- + 6 e- ------> 2 Cr3+ + 7 H2O
oxidation half reaction
C5H10O ------> C5H8O
C5H10O ------> C5H8O + 2H+
C5H10O ------> C5H8O + 2H+ + 2e-
now add the both euations
14 H+ + Cr2O72- + 6 e- ------> 2 Cr3+ + 7 H2O
C5H10O ------> C5H8O + 2H+ + 2e-
in order to get equate the electrons second euation we have to multyply with 3
3C5H10O ------> 3C5H8O + 6H+ + 6e-
now add both euations
14 H+ + Cr2O72- + 6 e- ------> 2 Cr3+ + 7 H2O
3C5H10O ------> 3C5H8O + 6H+ + 6e-
net Cr2O72- + 3C5H10O + 8H+ ------> 3C5H8O + 2 Cr3+ + 7 H2O
Get Answers For Free
Most questions answered within 1 hours.